To solve this problem you must follow the proccedure below:
a<span>. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(</span>πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of <span>the cracker remaining is:
</span><span>
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=</span>πr²/4
A=π(3 cm)²/4
A=7.06 cm²
<span>
The area of</span><span>of the cracker remaining is:
</span><span>
At=Area of a square-Area of quarter circle
At=L</span>²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
<span>
b. About how many bites can you get from the entire cracker?</span>
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
Answer:
150°
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u><em>AAS theorem: </em></u><em>If two angles and a non-included side of one triangle are congruent to corresponding two angles and a non-included side of second triangle, then the triangles are congruent.</em>
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1). ∠N ≅ ∠L Given
2). JK ≅ MK Given
3). ∠JKN ≅ ∠MKL Vertical
4). ΔJKN ≅ ΔMKL AAS theorem of congruence.
Answer: " n = - 4 " .
<u>__________</u>
<u>Step-by-step explanation</u>:
<u>Given</u>:
-n + 8 = 12 ; solve for "n" ;
Subtract "8" from each side of the equation:
-n + 8 - 8 = 12 - 8 ;
to get:
-n = 4 ;
Which is the same as:
-1n = 4 ;
Divide each side of the equation by "-1" ; to isolate "n" on one side of the equation; and to solve for "n" :
-1n / -1 = 4 / -1 ;
to get:
" n = - 4 " ; which is our answer.
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Now, let's check our answer:
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→ by plugging in our value obtained for "n" ; which is " - 4 " ;
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-(-4) + 8 ≟ 12 ?? ;
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From the "left-hand sign" of the equation:
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" - (-4) = ⁺ 4 " ;
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<u>Note</u>: The opposite of negative value; or the negative of a negative value; is equal to that very positive value.
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⇒ " 4 + 8 ≟ 12 ? ;
⇒ " 12 ≟ 12 ? ; Yes!
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The correct answer is: " n = - 4 " .
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Hope this helps! Best wishes!
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