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3 years ago

Write the expression: the sum of the quantity h and 2 divided by 4.

Mathematics

2 answers:

gtnhenbr [62]3 years ago

7 0

<h2>Answer:</h2>

<u>The expression is</u><u> (h+2) / 4</u>

<h2>Step-by-step explanation:</h2>

The expression can be written as follows

WE have 2 quantities h and 2

Their sum can be written as h+2

Now

We have the sum divided by 4

so it can be written as

(h+2) / 4

Serjik [45]3 years ago

6 0

H + 2 divided by 4

Please mark as brainliest!

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Step-by-step explanation:

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2 years ago

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(-7x∧5 + 14 - 2x) + (10x∧4 + 7x + 5x∧5)

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$-7x^5 + 5x^5 +10x^4 -2x + 7x + 14= -2x^5 +10x^4 +5x + 14$

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3 years ago

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2 years ago

graph the line that passes through the points (-8,9) and (4,-3) what are the x and y intercepts for this line someone help pleas

VashaNatasha [74]

Answer:

(0,1)- y intercept (1,0) x intercept

Step-by-step explanation:

first lets write this equation in slope intercept form: y=mx+b

m=slope

b=y intercept

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(y2-y1)/(x2-x1)

y2=-3

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x2=4

x1=-8

(-3-9)/(4--8)=-12/12=-1

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y=-1x+b

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3 years ago

A 10 ft pole has a support rope that extends from the top of the pole to the ground. The rope and the ground form a 30 degree an

mr Goodwill [35]

Answer:

The length of rope is 20.0 ft . Hence, <u>option (1) </u> is correct.

Step-by-step explanation:

In the figure below AB represents pole having height 10 ft and AC represents the rope that is from the top of pole to the ground. BC represent the ground distance from base of tower to the rope.

The rope and the ground form a 30 degree angle that is the angle between BC and AC is 30°.

In right angled triangle ABC with right angle at B.

Since we have to find the length of rope that is the value of side AC.

Using trigonometric ratios

$\sin C=\frac{\text{perpendicular}}{\text{hypotenuse}}$

$\sin C=\frac{AB}{AC}$

Putting values,

$\sin 30^\circ} =\frac{10}{AC}$

We know, $\sin 30^\circ}=\frac{1}{2}$

$\frac{1}{2} =\frac{10}{AC}$

On solving we get,

AC= 20.0 ft

Thus, the length of rope is 20.0 ft

Hence, <u>option (1)</u> is correct.

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2 years ago

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