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Brums [2.3K]
3 years ago
11

Sam makes about 79% of his free throws. he shoots 60 free throws. about how manywill he make?

Mathematics
2 answers:
Fudgin [204]3 years ago
6 0
The total amount of freethrows Sam will make is approximately 47 Freethrows
Formula:
(60 * 0.79)
nataly862011 [7]3 years ago
5 0
Hey You!

60 * 79% = 47.4

You can solve it by:

(60 ÷ 100 × 79 = 47.4)

Sam will make 47.4 of his throws.
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78% of the class completed their homework last night. What fraction of the class completed their homework?
mixas84 [53]

Answer:

\frac{39}{50}

Step-by-step explanation:

=> 78% makes:

=> \frac{78}{100}

<u><em>In simplest form:</em></u>

=>\frac{39}{50}

3 0
3 years ago
Read 2 more answers
Right triangle FGH has midsegments of 15,36, and 39 centimeters given that area of a triangle is represented by the formula A=1/
Schach [20]

Answer:

Step-by-step explanation:

according to the midsegment theorem, a midsegment of a triangle is parallel to a side of a triangle and its length is 1/2 length of the side.

1/2FG= 15, SO FG=30,

1/2 GH=36 SO GH=72

AREA = 1/2(72*30)=1080 CM^2

3 0
3 years ago
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A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
2 years ago
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Kiera is in her last year of college at the University of Houston. She has a scholarship that pays 75% of her costs. Her classes
sergiy2304 [10]
If the scholarship pays 75% of her classes cost, that means that she has to pay the 25% remaining of the classes cost so if we calculate it as follow:

0.25 * $14,000 = $3,500 
 =================================================================
Another method to understand:
if the scolarship pays 75% of her classes that will be 
0.75* $14,000 = $10,500

now she has to pay the remaining of the total cost and that will be 
$14,000 - $10,500 = $3,500.

5 0
3 years ago
What is bigger 4,000mg or 5g
uysha [10]
5g is bigger then 4,000mg

5 0
3 years ago
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