Question

The area of a bulletin board is 52 square feet. The length is 3 feet less than4 times the width. Find the length and width

Answer 1

Answer:

The length of the bulletin board is $13\ ft$

The width of the bulletin board is $4\ ft$

Step-by-step explanation:

Let

x-----> the length of the bulletin board

y-----> the width of the bulletin board

we know that

The area of the rectangle (bulletin board) is equal to

$A=xy$

we have

$A=52\ ft^{2}$

so

$52=xy$ ------> equation A

$x=4y-3$ ------> equation B

substitute equation B in equation A and solve for y

$52=(4y-3)y$

$4y^{2}-3y-52=0$

Using a graphing calculator------> solve the quadratic equation

The solution is

$y=4\ ft$

see the attached figure

Find the value of x

$x=4(4)-3=13\ ft$