The horizontal distance between the two balloons is 54.1478... meters.
<u><em>Explanation</em></u>
According to the below diagram, A and B are the positions of two balloons which are 48.2 meter and 61.0 meter above the ground respectively.
Horizontal distance between two balloons is AC, which is 
meter.
A person in the left balloon observes that the right balloon is 13.3° above the horizontal. That means, ∠BAC = 13.3°
According to the diagram, 
Now in right angle triangle ABC.....
So, the horizontal distance between the two balloons is 54.1478... meters.
34 = q + n
6.1 = .25q + .05n
-1.7 = -.05q - .05n
6.1 = .25q + .05n
4.4 = .2q
q = 22
22 of the coins are quarters.
Answer:
see below for a graph
Step-by-step explanation:
The first inequality does not include the "equal to" case, so its boundary is graphed with a dashed line. If we consider only the y term, we have y < ..., so the shading is below the line.
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The second inequality includes the "equal to" case, so its boundary line is solid. Again, considering only the y-term, we have y ≥ ..., so the shading is above the line.
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We find that points (-6, 0) and (0, 6) will satisfy both inequalities, as will any point in the doubly-shaded area.
Answer:
$15, brainliest please
Step-by-step explanation:
Answer:
m=15
Step-by-step explanation:
BODMAS
6m+6+7-3m=-32
collect like terms
6m-3m+6+7=-32
3m+13=-32
3m=-32-13
3m=45
m=45/3
m=15
