Answer:
An adult ticket is 17
A childs ticket costs 12 dollars
Step-by-step explanation:
Let a = adult price
c = child price
3a + 4c = 99
2a + 3c = 70
Multiply the first equation by 2
2(3a + 4c) = 99*2
6a + 8c = 198
Multiply the second equation by -3
-3 (2a + 3c) = 70*-3
-6a -9c = -210
Add these new equations together
6a + 8c = 198
-6a -9c = -210
----------------------
-c = -12
Multiply by -1
c = 12
A childs ticket costs 12 dollars
Now we need to find the price of an adult ticket
2a + 3c = 70
2a + 3(12) = 70
2a +36 = 70
Subtract 36 from each side
2a +36-36 =70-36
2a = 34
Divide by 2
2a/2 = 34/2
a = 17
An adult ticket is 17
A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.
b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.
c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.
d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.
.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
