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2 years ago

12

Write an equation in point-slope form of the line that passes through the two given points. Use the first point to write the equ

ation. (4,7) and (5, 1)

1 answer:

a_sh-v [17]2 years ago

5 0

Answer:
(-1,6)
Explanation:
use (y1-y2), (x1-x2)

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Will mark Branliest! Need help ASAP

Neko [114]

Answer:

12/2

Step-by-step explanation:

An integer is neither a fraction nor a decimal, but in this case you can simplify 12/2 to 6 which is a whole number making it an integer. Hope you found this helpful!

8 0

3 years ago

Read 2 more answers

Jason solved the following equation to find the value for x.

Ainat [17]

Plug in 6.5 for x.
-8.5x-3.5x=-78
-8.5(6.5)-3.5(6.5)=-78
-55.25-22.75=-78
-78=-78

5 0

1 year ago

Question 3 (1 point)

Virty [35]

Answer:

The answer to your question is (4, 6)

Step-by-step explanation:

Data

E ( 9 , 7 )

F ( - 1, 5)

Formula

$Xm = \frac{x1 + x2}{2}$

$Ym = \frac{y1 + y2}{2}$

Substitution and simplification

$Xm = \frac{9 -1}{2}$

$Xm = \frac{8}{2}$

Xm = 4

$Ym = \frac{7 + 5}{2}$

$Ym = \frac{12}{2}$

Ym = 6

Result

(4 , 6)

7 0

3 years ago

Click on the graphic to select the figure that would make the following a reflection in line k

Roman55 [17]

I remember answering the same question, but you didn't attach any photos. But I remember that the answer is the first one.

I hope I helped. Stay safe and God bless!

- Eli <3

6 0

3 years ago

For the following pair of functions, find (f+g)(x) and (f-g)(x).

ch4aika [34]

Given:

The functions are

$f(x)=4x^2+7x-5$

$g(x)=-9x^2+4x-13$

To find:

The functions $(f+g)(x)$ and $(f-g)(x)$ .

Solution:

We know that,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=4x^2+7x-5-9x^2+4x-13$

$(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)$

$(f+g)(x)=-5x^2+11x-18$

And,

$(f-g)(x)=f(x)-g(x)$

$(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)$

$(f+g)(x)=4x^2+7x-5+9x^2-4x+13$

$(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)$

$(f-g)(x)=13x^2+3x+8$

Therefore, the required functions are $(f+g)(x)=-5x^2+11x-18$

and $(f-g)(x)=13x^2+3x+8$ .

7 0

3 years ago