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Nikitich [7]
3 years ago
8

The cost of 10 oranges is 1 dollar what is the cost of 5 dozen oranges ?

Mathematics
2 answers:
Ivahew [28]3 years ago
6 0
Don't listen to me. Listen to Shaundavid XD
jeka57 [31]3 years ago
6 0
The oranges will cost 6$
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If cos x = .75, what is sin x?
Brilliant_brown [7]
ArcCos (.75) = x = 41.409

plug the x value into sin x and solve it

You will find that sin x = 0.66

Hope this helps
3 0
4 years ago
Read 2 more answers
Need help extra points and mark brainlessly
yaroslaw [1]
The answer is 6.1 gosh its making me type so many letters to answer ok i think im good now
6 0
3 years ago
Plz help me with this one..
Virty [35]

Answer:

The equations 3·x - 6·y = 9 and x - 2·y = 3 are the same

The possible solution are the points (infinite) on the line of the graph representing the equation 3·x - 6·y = 9 or x - 2·y = 3 which is the same line

Step-by-step explanation:

The given linear equations are;

3·x - 6·y = 9...(1)

x - 2·y = 3...(2)

The solution of a system of two linear equations with two unknowns can be found graphically by plotting the two equations and finding the coordinates of the point of intersection of the line graphs

Making 'y' the subject of both equations gives;

For equation (1);

3·x - 6·y = 9

3·x - 9 = 6·y

y = x/2 - 3/2

For equation (2);

x - 2·y = 3

x - 3 = 2·y

y = x/2 - 3/2

We observe that the two equations are the same and will have an infinite number of solutions

5 0
3 years ago
Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematic
pishuonlain [190]

Answer:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no

Step-by-step explanation:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no

7 0
3 years ago
Solution to the inequality 16x−33x<37x+27.
astra-53 [7]

<em><u>The solution to the inequality is:</u></em>

x>\frac{-1}{2}

<em><u>Solution:</u></em>

Given inequality is:

16x-33x

We have to find the solution to given inequality

\mathrm{Add\:similar\:elements:}\:16x-33x=-17x

-17x

\mathrm{Subtract\:}37x\mathrm{\:from\:both\:sides}

-17x-37x

Simplify the above inequality

-54x

\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)}

Remember that, change the inequality sign if you divide or multiply both sides by a negative number

If you divide or multiply both sides by a positive number,the inequality sign will not change

\left(-54x\right)\left(-1\right)>27\left(-1\right)\\\\54x>-27

\mathrm{Divide\:both\:sides\:by\:}54

\frac{54x}{54}>\frac{-27}{54}\\\\x>-\frac{1}{2}

Thus the solution to inequality is found

3 0
4 years ago
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