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In-s [12.5K]
2 years ago
13

Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematic

al notation, and clearly identify the claim and type of testing.
Mathematics
1 answer:
pishuonlain [190]2 years ago
7 0

Answer:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no

Step-by-step explanation:

For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:

Null hypothesis (H0): \mu \geq 2000

Alternative hypothesis (H1): \mu

And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no

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3 years ago
Which expression is equivalent
NemiM [27]
Answer:
6(3) - 4 + (3)^2

Explanation:
We will do this on two steps:
1- get g(x)-f(x)
2- substitute with x = 3

Step 1:
f(x) = 4-x^2
g(x) 6x
g(x) - f(x) = 6x - (4 - x^2)
               = 6x - 4 + x^2

Step 2:
Substitute with x = 3 as follows:
g(x) - f(x) at x = 3 is:
6(3) - 4 + (3)^2

Hope this helps :)

8 0
3 years ago
What is the area of a rectangle that has side lengths of 3/4 yard and 5/6 yard
Ahat [919]

We are asked to find the area of the rectangle that has side lengths of 3/4 yard and 5/6 yard.

We know that area of rectangle is width times length.

To find the area of the given rectangle we will multiply both side lengths as:

\text{Area of rectangle}=\text{Width}\times \text{Length}

\text{Area of rectangle}=\frac{3}{4}\text{ yard}\times\frac{5}{6}\text{ yard}

\text{Area of rectangle}=\frac{3}{4}\times\frac{5}{6}\text{ yard}^2

\text{Area of rectangle}=\frac{1}{4}\times\frac{5}{2}\text{ yard}^2

\text{Area of rectangle}=\frac{1\times5}{4\times2}\text{ yard}^2

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Therefore, the area of the given rectangle would be \frac{5}{8} square yards.

5 0
3 years ago
Solve the following system of equations: −2x + y = 1 −4x + y = −1
Liula [17]
Hello!

-2x + y = 1
-4x + y = -1

You can subtract these equations from each other to eliminate y

2x = 2

Divide both sides by 2

x = 1

Put this into one of the original equations

-2(1) + y = 1

Combine like terms

-2 + y = 1

Add 2 to both sides

y = 3

The answer is D) (1, 3)

Hope this helps!
6 0
3 years ago
Read 2 more answers
A sector with a central angle measure of \purpleD{175\degree}175°start color #7854ab, 175, degree, end color #7854ab has a radiu
Alisiya [41]

Answer: 219.94\ cm^2

Step-by-step explanation:

Given

The central angle of a sector measures 175^{\circ}

The radius of the circle is r=12\ cm

The area of the sector is given by

\Rightarrow A=\dfrac{\theta }{360^{\circ}}\pi r^2

Insert the values

\Rightarrow A=\dfrac{175^{\circ}}{360^{\circ}}\cdot \pi \times 12^2\\\\\Rightarrow A=219.94\ cm^2

8 0
3 years ago
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