G must be which measure for this quadrilateral to be a parallelogram?
2 answers:
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Step-by-step explanation:
Hey there!
The equation, of a st. line that passes through point (5,9) is,
Put the values,
It is 1st equation.
Now, another equation is,
y = 3x-1.........(ii)
Comparing the equation with y = mx+c.
Slope (m2)= 3
As per the parallel lines,
m1=m2=3
Putting,
the value of m1 in equation(i)
(y-9)= 3(x-5)
y-9= 3x - 15
y = 3x - 6.
So, Krista equation is correct.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>