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3 years ago

I need helppppp......

Mathematics

1 answer:

Roman55 [17]3 years ago

3 0

Answer:

l and n are parallel

Step-by-step explanation:

360° around a point

65° x 2 = 130

360 - 130 = 230

230/2 = 115

115 ° are corresponding angles

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Please Someone I need Help With 1-8

lina2011 [118]

5) k/35=3/7 : cross multiply
35*3=7k : simplify
105=7k : divide both sides of the equation by 7
k=15

6) 3/t=18/24 :cross multiply
18t=24*3 :simplify
18t=72 : divide both sides of the equation by 18
t=4

7) 10/8.4 = 5/m :cross multiply
10m=5 * 8.4 :simplify
10m=42 :divide both sides by 10
m=4.2

8 0

3 years ago

An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de

Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

$P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721$

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

$P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have:

$P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528$

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

$P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}$

Then we have

$P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453$

The sum of the probabilities is

$P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981$

8 0

3 years ago

A party rental company has chairs and tables for rent. The total cost to rent 5 chairs and

Alona [7]

Answer:

1 Chair= $1.25 1 table= $8.25

Step-by-step explanation:

5c+3t=31

2c+6t= 52

-2(5c+3t=31)

-10c-6t=-62

2c+6t=52

= -8c=-10

/-8 /-8

c= 1.25 or 1 1/4

2c+6t=52

2(1.25)+6t=52

2.5+6t=52

-2.5 -2.5

6t= 49.5

/6 /6

t= 8 1/4

5 0

2 years ago

What is the slope of the line that contains these points?

Liono4ka [1.6K]

Answer:

m=-3/7

Step-by-step explanation:

(-4,2), (-3,5)

x1 y1 x2 y2

m=y2-y1

x2-x1

m=5-2

-3-4

m=3

-7

m=-3/7

3 0

3 years ago

The finance charge you will pay in dollars is the only thing you need to know about a loan

Fudgin [204]

The finance charge you will pay in dollars is the only thing you need to know about a loan is false

5 0

3 years ago