Answer:
1. C. 28/54
2. A. 5/22
Step-by-step explanation:
1. Simplify each fraction to see which of the four are equal to 4/9.
2. Convert each to a decimal to see which is between 2/11 and 3/11.
Answer:
Step-by-step explanation:
y - 8 = -2(x - 6)
y - 8 = -2x + 12
y = -2x + 20
$330
Get 1/4 of $440 by multiplying 440 by .25 or dividing 440 by 4
You should get 110
Then subtract that from 440
440-110=330
Answer:
![L_2 = 2\frac{2}{15}\ ft](https://tex.z-dn.net/?f=L_2%20%3D%202%5Cfrac%7B2%7D%7B15%7D%5C%20ft)
Step-by-step explanation:
Given
Original
![Length(L_1) = 8\ in](https://tex.z-dn.net/?f=Length%28L_1%29%20%3D%208%5C%20in)
![Height (H_1) = 15\ in](https://tex.z-dn.net/?f=Height%20%28H_1%29%20%3D%2015%5C%20in)
New
![Height (H_2) = 4\ ft](https://tex.z-dn.net/?f=Height%20%28H_2%29%20%3D%204%5C%20ft)
Required
Determine the new length (L2)
Since the original photographs was blown up; the original and the new photographs would have the same ratio
i.e.
![Ratio = L_1 : H_1](https://tex.z-dn.net/?f=Ratio%20%3D%20L_1%20%3A%20H_1)
and
![Ratio = L_2 : H_2](https://tex.z-dn.net/?f=Ratio%20%3D%20L_2%20%3A%20H_2)
Equate both ratios
![L_1 : H_1 = L_2 : H_2](https://tex.z-dn.net/?f=L_1%20%3A%20H_1%20%3D%20L_2%20%3A%20H_2)
Rewrite as fraction
![\frac{L_1}{H_1} = \frac{L_2}{H_2}](https://tex.z-dn.net/?f=%5Cfrac%7BL_1%7D%7BH_1%7D%20%3D%20%5Cfrac%7BL_2%7D%7BH_2%7D)
Substitute values for L1, H1 and H2
![\frac{8}{15} = \frac{L_2}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B15%7D%20%3D%20%5Cfrac%7BL_2%7D%7B4%7D)
Multiply both sides by 4
![4 * \frac{8}{15} = \frac{L_2}{4} * 4](https://tex.z-dn.net/?f=4%20%2A%20%5Cfrac%7B8%7D%7B15%7D%20%3D%20%5Cfrac%7BL_2%7D%7B4%7D%20%2A%204)
![4 * \frac{8}{15} = L_2](https://tex.z-dn.net/?f=4%20%2A%20%5Cfrac%7B8%7D%7B15%7D%20%3D%20L_2)
![\frac{4 * 8}{15} = L_2](https://tex.z-dn.net/?f=%5Cfrac%7B4%20%2A%208%7D%7B15%7D%20%3D%20L_2)
![\frac{32}{15} = L_2](https://tex.z-dn.net/?f=%5Cfrac%7B32%7D%7B15%7D%20%3D%20L_2)
![2\frac{2}{15} = L_2](https://tex.z-dn.net/?f=2%5Cfrac%7B2%7D%7B15%7D%20%3D%20L_2)
![L_2 = 2\frac{2}{15}\ ft](https://tex.z-dn.net/?f=L_2%20%3D%202%5Cfrac%7B2%7D%7B15%7D%5C%20ft)
The new length must be ![2\frac{2}{15}\ ft](https://tex.z-dn.net/?f=2%5Cfrac%7B2%7D%7B15%7D%5C%20ft)