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vodomira [7]
3 years ago
14

Food A contains 150 calories in 3/4 of a serving.

Mathematics
1 answer:
Alex777 [14]3 years ago
7 0

Answer:

Food B has fewer calories.

Step-by-step explanation:

To find the unit rate we had to transfer both to have the denominator. To do that we have to find a common denominator both 4 and 3 have. The common denominator is 12. We then use 12 as a denominator and solve. (Sorry I don't really know how to explain.)

Food A=

12 ÷ 4 is 3, 3 × 3  = 9.

9/12

Food B=

12 ÷ 3 = 4, 4 × 2 = 8.

8/12

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Answer:

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Step-by-step explanation:

8 0
3 years ago
20 is what percent of 52
Maslowich
The process here is finding out the smallest number's % towards the largest number.

Divide 20 by 52:
20/52 = 0.38 (estimated) | This is the % in decimal form, which is 38%.

Conclusion: 20 is 38% of 52.

{---Further Elaboration for Future Reference---}

Finding the Smallest Number:

What number is 25% of 60?

Multiply 60 by the decimal form of 25%.
60 * 0.25 = 15 | 15 is 25% of 60.

Finding the Percentage. (Like what we already did.)

30 is what percent of 150?

Divide 30 by 150.
30/150 = 0.2 | 30 is 20% of 150.

Finding the Largest Number.

12 is 30% of what number?

Divide 12 by the decimal form of 30%.
12/0.3 = 40 | 12 is 30% of 40.

I hope this helps, have a great rest of your day! ^ ^
| | Ghostgate | |
5 0
3 years ago
Read 2 more answers
In a group of Explore students, 38 enjoy video games, 12 enjoy going to the movies and 24 enjoy solving mathematical problems. O
Elodia [21]

Answer:

The number of students that like only two of the activities are 34

Step-by-step explanation:

Number of students that enjoy video games, A = 38

Number of students that enjoy going to the movies, B = 12

Number of students that enjoy solving mathematical problems, C = 24

A∩B∩C = 8

Here we have;

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(B∩C) -n(A∩C) + n(A∩B∩C)

= 38 + 12 + 24 - n(A∩B) - n(B∩C) -n(A∩C) + 8

Also the number of student that like only one activity is found from the following equation;

n(A) - n(A∩B) - n(A∩C) + n(A∩B∩C) + n(B) - n(A∩B) - n(B∩C) + n(A∩B∩C) + n(C) - n(C∩B) - n(A∩C) + n(A∩B∩C) = 30

n(A) + n(B) + n(C) - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 3·n(A∩B∩C) = 30

38 + 12 + 24 - 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) + 24 = 30

- 2·n(A∩B) - 2·n(A∩C) - 2·n(B∩C) = -68

n(A∩B) + n(B∩C) + n(A∩C) = 34

Therefore, the number of students that like only two of the activities = 34.

8 0
3 years ago
Professor Tangent was stumped. His research assistant had given him a riddle but she simply could not solve. Help the professor!
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Answer:

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8 0
3 years ago
The comma after "however" should be removed
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No it shouldent

Step-by-step explanation:

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