24,48,72,96,120,144,168,192,216,240,264...360
90,180,270,360
LCM of 24 and 90 is 360
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hope it helps
We are given
Vertical asymptotes:
Firstly, we will factor numerator and denominator
we get
![y=\frac{(x-1)(x-3)}{(x-3)(x+3)}](https://tex.z-dn.net/?f=%20%20y%3D%5Cfrac%7B%28x-1%29%28x-3%29%7D%7B%28x-3%29%28x%2B3%29%7D%20%20)
We can see that (x-3) is common in both numerator and denominator
so, we will only set x+3 to 0
and then we can find vertical asymptote
![x+3=0](https://tex.z-dn.net/?f=%20%20x%2B3%3D0%20%20)
![x=-3](https://tex.z-dn.net/?f=%20%20x%3D-3%20%20)
Hole:
We can see that (x-3) is common in both numerator and denominator
so, hole will be at x-3=0
![x=3](https://tex.z-dn.net/?f=%20%20x%3D3%20%20)
Horizontal asymptote:
We can see that degree of numerator is 2
degree of denominator is also 2
for finding horizontal asymptote, we find ratio of leading coefficients of numerator and denominator
and we get
y=1
now, we can draw graph
Graph:
This is the concept algebra.
Volume of of paint that is required to paint large shipping crate is a liters.
suppose the volume of this crate is x cubic units.
The volume of the next crate to be painted will be 2x cubic units.
Hence the amount of paint required to paint the crate will be:
(volume of bigger crate)/(volume of smaller crate)×(volume of liters required to paint the first crate)
=(2x)/(x)×a
=2a liters
To paint the new crate 2a liters of oil is needed.
Answer:
There are 47.12 liters in 12.4 gallons of gasoline.
Option C is correct option.
Step-by-step explanation:
Total Gasoline bought = 12.4 gallons
We are given:
1 gallons = 3.8 liters
So.=, we need to find how many liters in 12.4 gallons of gasoline
1 gallon = 3.8 liters
12.4 gallon = 3.8*12.4
= 47.12 liters
So, there are 47.12 liters in 12.4 gallons of gasoline.
Option C is correct option.
Answer:
The answer is 60 and 80
Step-by-step explanation: