Answer:
C) Similar-SAS
Step-by-step explanation:
Here,
BSE ~ TES
Now,
BS = TE (:• being corresponding side )
BSE = TES (:• Being Corresponding angle
SE = SE (:•Being corresponding side)
Therefore,
the given triangle is similar by
SAS axiom
Sqrt 363 - 3 sqrt27
= sqrt(121* 3) - 3 sqrt (9*3)
= sqrt 121* sqrt3 - 3 * sqrt 9 * sqrt3
= 11 sqrt3 - 3* 3 sqrt3
= 11 sqrt3 - 9 sqrt3
= 2 sqrt3 Answer
Answer:
The correct answer is D) areas, probability, and relative frequencies
Step-by-step explanation:
This is because each of these terms refers to an amount of space surrounding the mean on the normal distribution curve. Each of them let's us know how likely a spot is to have a value within it.
The z-score would not fit this as it identifies the value and how far away a single spot on the graph would be.
Who is my work I think the answer would be -190
Answer:
The height of the new cones will be 16.5 inches.
Step-by-step explanation:
We know that,
The volume of a cone is,

Where, r is the radius of the cone,
h is the height of the cone,
In the original cone,
r = 22 inches,
h = 66 inches,
Thus, the volume would be,

Also, for the new cone,
r = 44 inches,
Let H be the height,
So, the volume of the new cone would be,

According to the question,



Hence, the height of the new cones will be 16.5 inches.