Jerry is paid $6 per hour. He worked 1 hour and 10 minutes.
So, we'll need to find out how much he is paid per minute. We'll divide $6 by 60 minutes; which will give us $0.10 per minute.
For the 10 minutes extra he worked, we'll multiply by $0.10.
10 x 0.10 = 1
This shows that he earned an extra $1 for the additional 10 minutes he worked.
He earned $6 for the full hour plus $1 for the additional 10.
6 + 1 = 7
Therefore, Jerry earned $7.00 for his time worked on that day.
Answer:
number c
Step-by-step explanation:
.............. just for filling 20 characters
Answer:
1, x/3, x^2/9, x^3/27, x^4/81
x^4 +3x^3+9x^2+27x+81
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81
Step-by-step explanation:
(x/3) ^i
i=0 (x/3)^0 = 1
i=1 (x/3)^1 = x/3
i=2 (x/3)^2 = x^2/3^2 = x^2/9
i=3 (x/3)^3 = x^3/3^3 =x^3/27
i=4 (x/3)^4 = x^4/3^4 =x^4/81
The sum is
1+(x/3) + x^2/9 + x^3/27 + x^4/81
We need a common denominator of 81
1*81/81 + x/3 *27/27 + x^2/9 *9/9 + x^3/27 *3/3 + x^4/81
81+27x + 9x^2 + 3x^3 +x^4
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81
Rewriting from largest power to smallest power
x^4 +3x^3+9x^2+27x+81
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81
(y-y1) = m( x-x1)
y+5=2/3(x-6)
y +5 = 2/3. x - 4
y = 2/3 x - 9
Answer:
There is no option in the question given.
However, In logic and probability theory, two events are mutually exclusive or disjoint if they cannot both occur at the same time. A clear example is the set of outcomes of a single coin toss, which can result in either heads or tails, but not both.
