Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.
![\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7Bhyperbolas%2C%20horizontal%20traverse%20axis%20%7D%20%5C%5C%5C%5C%20%5Ccfrac%7B%28x-%20h%29%5E2%7D%7B%20a%5E2%7D-%5Ccfrac%7B%28y-%20k%29%5E2%7D%7B%20b%5E2%7D%3D1%20%5Cqquad%20%5Cbegin%7Bcases%7D%20center%5C%20%28%20h%2C%20k%29%5C%5C%20vertices%5C%20%28%20h%5Cpm%20a%2C%20k%29%5C%5C%20c%3D%5Ctextit%7Bdistance%20from%7D%5C%5C%20%5Cqquad%20%5Ctextit%7Bcenter%20to%20foci%7D%5C%5C%20%5Cqquad%20%5Csqrt%7B%20a%20%5E2%20%2B%20b%20%5E2%7D%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
Answer:
5.2
Step-by-step explanation:
To find the height of the plant after 7 weeks, we need to find out the equation of the line of best fit and plug in 7 for x. We already have our y - intercept, which is 1, and we have a point on the x axis for which the y coordinate is an integer, (5, 4). Since we already have the y - intercept of +1 we have y = mx + 1. Since this applies to (5,4) we can plug this in to our equation. This is then 4 = 5m + 1. Subtracting 1 from both sides, we get 3 = 5m. Dividing by 5, we receive m = 3/5. Since now we have our slope, we can plug in 7 and find out our answer. Plugging in 7 we receive, y = 3/5 * 7 + 1, which is equal to y = 4.2 + 1. This means that y = 5.2, so 5.2 is our answer.
Answer:
412in
Step-by-step explanation:
Ok so the only ones that we know for sure are 4 = 1, 6=8, 7=9 and you can’t really do all that much with 2,3,5 because it’s not as obvious
