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Marysya12 [62]
2 years ago
9

Find the value of x y, and z in the parallelogram below.

Mathematics
1 answer:
EastWind [94]2 years ago
6 0
Let A be the angle of 79 degrees
B be the angle of (5y-4) degrees
C be the angle of (x+5) degrees
D be the angle of (9z-7) degrees
According to the property of parallelogram
Opposite angles are equal
We get, angle A = angle C
Since angle A = 79 degrees
And angle C = (x+5) degrees
We get, x+5=79
=> x=79-5=74.

Angle B = Angle D
(5y-4)=(9z-7)
Since there’s two variables here, we can’t use the property of “opposite angles are equivalent”
We have to use another property which is adjacent angles are equal
Therefore, we can find angle D
Angle D + Angle A=180
=> 9z-7 =180-79
z=108/9
z=12
Since (5y-4)=(9z-7)
Substitute z=12 in
We get, 5y-4=101
y= 105/5
y= 21
Therefore, x=74, y=21 and z=12.
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see below

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shusha [124]
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explain how you can use a straightedge and a protractor to show that each angle you formed by a bisector is one-half the origina
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I'LL GIVE YOU BRAINIEST!<br> 1 1/5 · x/3 = 9/10 solve for x
joja [24]

\huge\text{Hey there!}

\huge\textbf{Equation:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Solve:}

\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{1\times5+1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{5 + 1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\mathbf{\rightarrow \dfrac{6}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow \dfrac{2}{5}x = \dfrac{9}{10}}

\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}

\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}

\huge\textbf{Simplify it:}

\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}

\mathbf{\rightarrow x = \dfrac{5\times9}{2\times10}}

\mathbf{\rightarrow x = \dfrac{45}{20}}

\mathbf{\rightarrow x = \dfrac{45\div5}{20\div5}}

\mathbf{\rightarrow x = \dfrac{9}{4}}

\mathbf{x \approx 2 \dfrac{1}{4}}

\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

8 0
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64/4 is 16 if that's what you meant.
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