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Andreyy89
3 years ago
11

Which points are on the line that connects points (0, 4) and (1, 2)? Select all that apply.

Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0
The points that connect (0,4) and (1,2) are B, E and F. Please mark Brainliest and Hope this Helps
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Can someone plss help me I don't understand this!
Yanka [14]

Answer: 4. A

5. C

6. B

Step-by-step explanation:

5 0
3 years ago
I need the answer asap
eimsori [14]

Answer:

22873

Step-by-step explanation:

you have to put the value from 6-94 in n the given equation 5n+7.

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3 years ago
Sarah kicked a ball in the air. The function
Aleksandr-060686 [28]

Answer: The ball hits the ground at 5 s

Step-by-step explanation:

The question seems incomplete and there is not enough data. However, we can work with the following function to understand this problem:

f=30 t- 6t^{2} (1)

Where f models the height of the ball in meters and t the time.

Now, let's find the time t when the ball Sara kicked hits the ground (this is when f=0 m):

0=30 t- 6t^{2} (2)

Rearranging the equation:

6t^{2}-30 t=0 (3)

Dividing both sides of the equation by 6:

t^{2}-5 t=0 (4)

This quadratic equation can be written in the form at^{2}+bt+c=0, and can be solved with the following formula:  

t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} (5)  

Where:  

a=1  

b=-5  

c=0  

Substituting the known values:  

t=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(0)}}{2(1)} (6)  

Solving we have the following result:

t=5 s  This means the ball hit the ground 5 seconds after it was kicked by Sara.

6 0
3 years ago
12 3/8 divided by 3/4
oksano4ka [1.4K]

Answer:

32/2 or 16.5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLEASE HELP ME! 100 POINTS! ;( question 10, 11, 12, 13, 14, 15. I have a f in this class and could use your help a lot! I will l
MatroZZZ [7]

There are a lot of problems here so I'll try to be brief with each one so I don't add a lot of clutter

Problem 10) This is <u>arithmetic</u> because we subtract 6 from each term to get the next. This is the same as adding on -6. The common difference is d = -6. The first term is a = 1

Problem 11) <u>Neither</u>. The distance from 3 to 3/2 = 1.5 is 1.5 units, but the distance from 1.5 to 1 is 0.5 units. This implies there is no common difference value. The sequence is not arithmetic because of this. It's also not geometric either. To go from 3 to 3/2, we multiply by 1/2. But then going from 3/2 to 1, we multiply by 2/3. There is no common ratio r value.

Problem 12) This sequence is <u>geometric</u>. We divide each term by 3 to get the next, or put another way, we multiply each term by 1/3 to get the next term. The common ratio is r = 1/3. The first term is a = 108.

Problem 13) <u>Neither</u>. This is because going from term to term, we do not add the same amount each time. Example: from -2 to 4 we add 6, but then from 4 to -6 we add -10. So the sequence is not arithmetic. It's also not geometric either because we dont multiply by the same term each time. Eg: from -2 to 4, we multiply by -2; but from 4 to -6 we multiply by -1.5

Problem 14) The next three terms are: <u>1, 1/4, 1/16</u>. This is found by multiplying each term by the common ratio r = 1/4, or you can think of dividing each term by 4. To get this common ratio, pick any term you want and divide it by its previous term. Example: term2/term1 = 16/64 = 1/4 = common ratio.

Problem 15) The next three terms are: <u>-432, 2592, -15552</u>. You multiply each term by the common ratio -6. Like with the previous problem, we divide any term over its previous one to get the common ratio, so for example, term2/term1 = -12/2 = -6 = common ratio.

3 0
3 years ago
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