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stira [4]
3 years ago
7

In how many ways can the eight rooks be placed on an 8-by-8 chessboard so that no two rooks can attack one another?

Mathematics
1 answer:
saul85 [17]3 years ago
7 0
You have a total of (8!)^2/8! and that gets you. 40,320
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kondaur [170]
L=16
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Set up a systems of equations: 
x=length 
y=width 

xy=336
x+5=y

Use substitution to solve: 
x(x+5)=336
x^2+5x=336 

Solve using factoring: 
x^2+5x-336=0
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Since length can't be negative, l=16 

To find width, plug length into the first equation: 
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So...
L=16
<span>W=21</span>
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Step-by-step explanation:

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