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3 years ago

Please help! posted picture of question

Mathematics

2 answers:

Rus_ich [418]3 years ago

8 0

The given equation is in point-slope form.

The general form of an equation in point slope form is:

$y- y_{1}=m(x- x_{1})$

Here m is the slope and $x_{1}$ and $y_{1}$ are the coordinates of the point.

So in given equation the slope is 2/3, and the coordinates of point are (1,3)

AnnZ [28]3 years ago

4 0

It is the point-slope form

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3 years ago

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d1i1m1o1n [39]

Given:

The given expression to find the nth term of the sequence is $d(n)=d(n-1) \cdot (-5)$

The first term of the sequence is $d(1)=8$

We need to determine the third term of the sequence.

Second term:

The second term of the sequence can be determined by substituting n = 2 in the nth term of the sequence.

Thus, we have;

$d(2)=d(2-1) \cdot (-5)$

$d(2)=d(1) \cdot (-5)$

$d(2)=8 \cdot (-5)$

$d(2)=-40$

Thus, the second term of the sequence is -40.

Third term:

The third term of the sequence can be determined by substituting n = 3 in the nth term of the sequence.

Thus, we have;

$d(3)=d(3-1) \cdot (-5)$

$d(3)=-40 \cdot (-5)$

$d(3)=120$

Thus, the third term of the sequence is 120.

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3 years ago

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zubka84 [21]

Answer: Number one would be 3x+2y+-14 and x+y=-4, second one is x=-3, y=7

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Solution: The standard deviation is used in conjunction with the mean to numerically describe distributions that are bell shaped. The mean measures the center of the distribution, while the standard deviation measures the spread of the distribution.

In normal distribution (bell shaped distribution) , the mean and standard deviation are used to describe its distribution. The mean measures the center of the distribution, while the standard deviation takes care of the spread of the distribution.

The mean of the normal distribution is $\mu$ and the standard deviation is $\sigma$