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nadya68 [22]
3 years ago
9

I need help do you guys know how to help me with this

Mathematics
1 answer:
Stells [14]3 years ago
7 0

Answer:

Quadratic, Linear, Exponential.

Step-by-step explanation:

You can find the average difference between rows. For example, in the first one, between the ys, it changes by 1, then 3, then 5, then 7. If you look at the changes between these you get 2 each time. Because you had to look at the differences twice, its quadratic. It's linear if you had to look at it once. Exponential you can just see if you can multiply the same constant between each row.

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Identify the linear term in the function of y = 2x2 − 5x − 12
MakcuM [25]

Answer:

The linear term is -5x

Step-by-step explanation:

The linear term is the term that has the degree equal to 1.

The given function is

y = 2x^2 − 5x − 12

here 2x^2 = quadratic term i.e having degree 2

-5x = linear term i.e having degree 1

-12 = constant

so, The linear term is -5x

4 0
3 years ago
The resulting figure after undergoing a transformation
vaieri [72.5K]

Answer:

New being?

Step-by-step explanation:

3 0
3 years ago
Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

4 0
3 years ago
Complete 6,7 for 5 points.
seraphim [82]

Answer:

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Step-by-step explanation:

4 0
3 years ago
Which equation is equivalent to y=23x−6?
photoshop1234 [79]
D. I think you meant to say 2/3 x so the only correct answer is d
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