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alina1380 [7]
3 years ago
8

In a Punkin’ Chunkin’ contest, the height (in feet)

Mathematics
1 answer:
Nikolay [14]3 years ago
5 0

a. At t=0, the pumpkin is 25 feet above the ground (Plug 0 into the equation and solve)

b. If you plug the equation in a graphing calculator and find the rightmost zero, you get t = 10.15 seconds.

c. The vertex (maximum point) of the graph is (5, 425). Therefore, the pumpkin reaches its maximum height of 425 feet after 5 seconds in the air.


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NNADVOKAT [17]
<h2>The required "option A) 20" is correct.</h2>

Step-by-step explanation:

Let x be the smaller than 4 ×10^{-2}.

To find, the number of times smaller is 2 × 10^{-3} than 4 × 10^{-2} = ?

∴ x = \dfrac{4\times 10^{-2}}{2\times 10^{-3}}

= 2 × 10^{-2} × 10^{3}

Using the identity,

a^{m}=\dfrac{1}{a^{-m}}

= 2 × 10^{-2+3}

Using the identity,

a^{m} \timesa^{n}=a^{m+n}

= 2 × 10^{1}

= 2 × 10

= 20

Thus, the required "option A) 20" is correct.

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Answer:

The explicit formula

a_n = 3 +0.25 (n-1)

The recursive formula

a_1 = 3                            for n=1

a_n = a_ {(n-1)} +0.25     if n>1

Step-by-step explanation:

If a sequence is arithmetical then the difference between any of its consecutive terms will be constant

3, 3.25, 3.5, 3.75,

3.25-3 = 0.25\\\\3.5-3.25 = 0.25\\\\3.75 -3.5 = 0.25

The difference between the consecutive terms remains constant so the sequence is arithmetic.

The explicit formula for an arithmetic sequence is:

a_n = a_1 + d (n-1)

Where d is the constant difference between the terms.

d = 0.25

a_1 is the first term of the sequence.

a_1 = 3

So

a_n = 3 +0.25 (n-1)

Finally, the recursive formula is:

a_1 = 3\\\\a_n = a_ {(n-1)} +0.25

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The answer to your question is F

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Y=2(5)+ 4
Y= 10+4
Y = 14
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