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Kaylis [27]
3 years ago
14

Which of the equations below is not a Linear Equation?

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0
The answer is part B
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PLS HELP ME !!!!<br> The last one is (x+2)^2 + (y-1) ^2 = 12
ladessa [460]

Answer:

its the first one or the last one

Step-by-step explanation:

i got the same thing on the graph sry

7 0
3 years ago
22. Write the equation in Slope-Intercept form of the line with an x-intercept of 2
Thepotemich [5.8K]

Answer:

y = \frac{1}{2} x - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (2, 0) and (x₂, y₂ ) = (0, - 1) ← coordinates of intercepts

m = \frac{-1-0}{0=2} = \frac{-1}{-2} = \frac{1}{2}

The y- intercept is - 1 ⇒ c = - 1

y = \frac{1}{2} x - 1

5 0
3 years ago
Proportions in Triangles (2)
forsale [732]

Answer:

  x = 6

Step-by-step explanation:

An angle bisector divides the segments on either side of it so they are proportional. That is ...

  x/12 = 5/10

  x = 12(5/10) = 6 . . . . . multiply by 12

6 0
3 years ago
Twins Isaac and Isaac where just born. Issac weighs 6 pounds 2 ounces and Isaiah weighs 5 pounds 4 ounces how many ounces do the
Ray Of Light [21]
182 ounces isthe answer
3 0
4 years ago
Lou has an account with $10,000 which pays 6% interest compounded annually. if to that account, lou deposits $5,000 at the begin
Tems11 [23]

ince the problem is only asking for 4 years, we can just calculated it out year by year. Recall the formula for compounding interest: A = P(1+r)n, where A is the total amount, P is the principle (amount you start with), r is the interest rate per period of time, and n is the number of periods (in this case, r is annual interest rate, so n is number of years). At the beginning (Year 0), Lou starts off with 10000: A = 10000 At the end of Year 1, Lou earned interest on that amount, plus he has deposited another 5000: A = 10000(1.08) + 5000 End of Year 2, Lou's interest from the year 0 amount has compounded, he has started earning interest on the amount deposited last year, and he deposits another 5000: A = 10000(1.08)2 + 5000(1.08) + 5000 End of Year 3, same idea. Lou has earned compounding interest on all existing deposits, and deposits another 5000: A = 10000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 End of Year 4, same idea: A = 10000(1.08)4 + 5000(1.08)3 + 5000(1.08)2 + 5000(1.08) + 5000 = 36135.45



7 0
3 years ago
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