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Korvikt [17]
3 years ago
12

What does 70.2 rounded to the nearest ten?

Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0

Answer:

70

Step-by-step explanation:

a_sh-v [17]3 years ago
6 0

Answer:

70

Step-by-step explanation:

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Hospitals typically require backup generators to provide electricity in the event of a power outage. Assume that emergency backu
JulsSmile [24]

Answer:

a) There is a 10.24% probability that both generators fail during a power outage.

b) There is an 89.76% probability of having a working generator in the event of a power outage, which is not high enough for the hospital.

Step-by-step explanation:

For each emergency backup generator, there are only two possible outcomes. Either they work correctly, or they fail. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

Assume that emergency backup generators fail 32% of the times when they are needed. So they work correctly 100-32 = 68% of the time. So p = 0.68

There are two generators, so n = 2

a. Find the probability that both generators fail during a power outage

This is P(X = 0)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.68)^{0}.(0.32)^{2} = 0.1024

There is a 10.24% probability that both generators fail during a power outage.

b. Find the probability of having a working generator in the event of a power outage. Is that probability high enough for the hospital? Assume the hospital needs both generators to fail less than 1% of the time when needed.

Either there are no working generators, or there is at least one working generator. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1024 = 0.8976

There is an 89.76% probability of having a working generator in the event of a power outage, which is not high enough for the hospital.

To be high enough for the hospital, this probability should be at least of 99%.

7 0
4 years ago
Cassie took 2 quizzes last week. She scored the same in each quiz.
ololo11 [35]

Answer:

since her score was -12 from being perfect

if she had scored 12 more points her score would have been perfect .

that is difference between her score and the perfect score o each quiz was <u>12</u>

8 0
3 years ago
My last question for the pre test
Sindrei [870]

Answer:

6

Step-by-step explanation:

5 0
3 years ago
Help me pls I don't know what I'm doing ​
emmasim [6.3K]

Answer:

B. 3.6

Step-by-step explanation:

I have no idea if this is right but my logic is 3.6 - 3.6 = 0

5 0
3 years ago
Read 2 more answers
Please answer it now in two minutes
Degger [83]

Answer:

47

Step-by-step explanation:

360-62-75-26-9=188

188/4=47

4 0
3 years ago
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