The sample is all voters in the district that think he’s doing a good job
If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Answer: 220.5 ft^2
Step-by-step explanation:
You separate it into shapes and sum the area of those. I made a triangle 15 by 15, a rectangle 4 by 15, a smaller rectangle 4 by 10, and a triangle 4 by 4
Answer:
3
Step-by-step explanation:
A dog buried 18 bones
On Monday he dug up 1/2 of the bones
On Tuesday he dug up 1/3 of the bones
= 1/2 × 18
= 9
= 1/3×18
= 6
Therefore the remaining bones still buried in the ground can be calculated as follows
= 9+6
= 15
= 18-15
= 3
Hence 3 bones are still buried in the ground