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Vilka [71]
4 years ago
13

On a multiple choice test, each question has 7 possible answers. If you make a random guess on the first question, what is the p

robability that you are correct? a. 1 b. 7 c. 1/7 d. 0
Mathematics
1 answer:
valkas [14]4 years ago
4 0

Answer:

c (1/7)

Step-by-step explanation:

You might be interested in
un campo de futbol tiene 100m de largo y 60m de ancho¿ Cuales son la longitud y la anchura del campo?
Alex Ar [27]

Answer:

328 pies de largo

196.8 pies de ancho

Step-by-step explanation:

Ya que las medidas dadas estan en metros, podemos usar esas medidas para calcular la longitud y anchura en pies.

100 metros de largo.

60 metros de ancho.

Si sabemos que 1m es igual a 3,28 pies, simplemente tenemos que multiplicar las medidas en metros por 3.28 y nos va dar la medida del campo en pies.

100 * 3.28 = 328 pies de largo

60 * 3.28 = 196.8 pies de ancho

8 0
3 years ago
NEED HELP URGENTLY!!!!!
Svet_ta [14]

A

substitute each point into the inequality and check validity of solution

A (4, 4)

4 ≤ 16 - 12 + 2 ⇒ 4 ≤ 6 → True hence valid solution

B (3, 3 )

3 ≤ 9 - 9 + 2 ⇒ 3 ≤ 2 → False hence not valid

C (1, 1 )

1 ≤ 1 - 3 + 2 ⇒ 1 ≤ 0 → False hence not valid

D (2, 2 )

2 ≤ 4 - 6 + 2 ⇒ 2 ≤ 0 → False hence not valid


7 0
4 years ago
Read 2 more answers
Find the value of each variable.<br>​
V125BC [204]

Answer:

see explanation

Step-by-step explanation:

Using the exact values of the trigonometric ratios

sin60° = \frac{\sqrt{3} }{2}, cos60° = \frac{1}{2}

sin45° = cos45° = \frac{1}{\sqrt{2} }

Using the sine ratio on the right triangle on the left

sin60° = \frac{opposite}{hypotenuse} = \frac{a}{4\sqrt{3} } = \frac{\sqrt{3} }{2}

Cross- multiply

2a = 4\sqrt{3} × \sqrt{3} = 12 ( divide both sides by 2 )

a = 6

Using the cosine ratio on the same right triangle

cos60° = \frac{adjacent}{hypotenuse} = \frac{c}{4\sqrt{3} } = \frac{1}{2}

Cross- multiply

2c = 4\sqrt{3} ( divide both sides by 2 )

c = 2\sqrt{3}

------------------------------------------------------------------------------------------

Using the sine/cosine ratios on the right triangle on the right

sin45° = \frac{a}{b} = \frac{6}{b} = \frac{1}{\sqrt{2} }

Cross- multiply

b = 6\sqrt{2}

cos45° = \frac{d}{b} = \frac{d}{6\sqrt{2} } = \frac{1}{\sqrt{2} }

Cross- multiply

\sqrt{2} d = 6\sqrt{2} ( divide both sides by \sqrt{2} )

d = 6

------------------------------------------------------------------------------------------------

a = 6, b = 6\sqrt{2}, c = 2\sqrt{3}, d = 6

3 0
3 years ago
Leila is participating in a
guapka [62]
She needs to ride 46 miles . to get this answer you multiply 61 by 6 and get 366. then you add  up all the numbers and get 320 then you subtract 366 by 320 . 

3 0
3 years ago
Helppppppppppppppppppppppppp
Nataliya [291]
Answer:
Choice A: stretched horoxontally by a factor of 2 and translated up by 3 units

Explanation:
The original graph is:
y = log(x)
The modified one is:
y = log(2x) + 3

We can note that 2 changes occured:
1- A 3 has beed added to the whole gaph. This means that the curve has been moved (translated) upwards by 3 units

2- The x inside the log is miltiplied by 2. This means that the graph is stretched horizontally by the factor added (2).

Combining these two, we will find that the correct choice is A

Hope this helps :)
3 0
3 years ago
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