All categories

3 years ago

HELP!!! CORRECT ANSWER NEEDED OR ELSE I FAIL ;-; STUDY ISLAND !!

Mathematics

1 answer:

Ket [755]3 years ago

5 0

Answer:

B. Step 2 uses the associative property, and step 3 uses the commutative property.

Step-by-step explanation:

The associative property lets you group terms for addition any way you like. It appears that in Step 2, the grouping is ...

4 + (1/6 + 3) + 5/6

The commutative property lets you change the order of any pair of terms involved in addition. It appears that in Step 3, the order of the terms within the group has been swapped.

4 + (3 + 1/6) + 5/6

_____

<em>Comment on associative and commutative properties</em>

What applies to terms in addition applies to factors in multiplication.

You might be interested in

20. What is the perimeter of a square that has a side length of 4x - 5y? (Show Work)

sammy [17]

Answer= 16x -20y

Perimeter of a square= 4( Side length)
Therefore, 4(4x -5y)
= 16x -20y
I think that is it cuz e can’t solve it any further

8 0

3 years ago

The annual growth rate of energy utilization in the world was 3.5% per year in the period between 1950 and 1973. How long would

nika2105 [10]

Answer:

Good Luck!

Step-by-step explanation:

4 0

3 years ago

I need the answer plssss

Artist 52 [7]

Answer: b drained the fastest I think

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Sorry I have trouble with math

Pavlova-9 [17]

Answer:

okkk budyyyyyyyysjsj

6 0

3 years ago

I need help with number 4

Nadusha1986 [10]

$\bf \begin{cases}
\quad3x+2y=-9\\
-10x+5y=-5
\end{cases}$

so hmm the idea behind the elimination, is to make the value atop or below, of either variable, the same but with a negative sign

so hmmm say... we'll eliminate "y"

so... let's see, we have 2y and 5y, both positive
what do we multiply 2y to get a negative -5y, that way, -5y +5y = 0 and poof it goes

well let's see, let's try "k" $\bf 2yk=-5y\implies k=-\cfrac{5y}{2y}\implies k=-\cfrac{5}{2}$

so.. if we multiply 2y by -5/2, we'll end up with -5y

well, let's multiply that first equation then by -5/2

$\bf \begin{array}{rllll}
3x+2y=-9&\qquad\times -\frac{5}{2}\implies &-\frac{15}{2}x-5y=\frac{45}{2}\\\\
-10x+5y=-5&\implies &-10x+5y=-5\\
&&---------\\
&&\frac{-35}{2}x+0\quad=\frac{35}{2}
\end{array}\\\\
-----------------------------\\\\
\cfrac{-35}{2}x=\cfrac{-35}{2}\implies \cfrac{-35x}{2}=\cfrac{-35}{2}\implies x=\cfrac{2}{-35}\cdot \cfrac{-35}{2}
\\\\\\
\boxed{x=1}$

so.. now we know x = 1.... so let's plug that in say hmmm 2nd equation

$\bf -10(1)+5y=-5\implies -10+5y=-5\implies 5y=5\implies\boxed{ y=1}$

3 0

4 years ago