Find the value of sinY
1 answer:
Answer:
Step-by-step explanation:
Please see the attached picture.
Let's find the value of the opposite side, XZ.
Applying Pythagoras' Theorem,
(XZ)² +(XY)²= (ZY)²
(XZ)² +16²= 65²
(XZ)²= 4225 -256 <em>(</em><em>bring</em><em> </em><em>constant</em><em> </em><em>to</em><em> </em><em>1</em><em> </em><em>side</em><em>)</em>
(XZ)²= 3969 <em>(</em><em>simplify</em><em>)</em>
<em>Square</em><em> </em><em>root</em><em> </em><em>both</em><em> </em><em>sides</em><em>,</em>
XZ=
XZ= 63 <em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>(simplify)</em>
sinY
= XZ/ ZY
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Answer:
She can visit the cities in 192 ways
Step-by-step explanation:
If Sally starts from city A and after going to 4 cities she returns to home,
then that can be in 4! = 24 ways. (permutation of 4 distinct objects)
If between the time she visits cities, she comes home once,
then cities can be visited in,
= 72 ways. (permutation of 4 distinct objects and choosing 1 gap among the 3 )
If between the time she visits cities, she comes home twice,
then cities can be visited in,
=72 ways. (permutation of 4 distinct objects and finding 2 gaps among the 3)
If between the time she visits cities, she comes home thrice,
then cities can be visited in,
= 24 ways. (permutation of 4 distinct objects and choosing 3 gaps among the 3)
Now, she can't come home more than thrice in between the time she visits cities (since there are 4 cities to visit only)
So, the number of ways she can visit cities = (24+ 72 + 72 + 24)
= 192