What are the coordinates of the terminal point determined by t=10pi/3
1 answer:
we know that
10*pi/3------> convert to degrees------> 10*180/3=600 degrees
600=360+240
240 degrees belong to the III quadrant
so
the x-coordinate is negative
the y-coordinate is negative
240°=180°+60°
60 degrees is the angle to find the terminal point
let
∅=60°
in the unit circle
r=1 units
x=-r*cos ∅----> x=-cos 60------> x=-(1/2)
y=-r*sin ∅----> y=-sin 60------> y=-(√3)/2
the point is
therefore
the answer is the option D
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Answer: 5.196152423
Step-by-step explanation: Logically considering it's a Rhombus all the sides are equal to each other. So you just need to find the area. In this case you find the area by multiplying the sin of the given angle by the square root of the given side. So, 6²×sin (60)=6²×√3/2=31.17691454. After finding the area you then have to divide the area by it's base to find the height. So, 31.17691454 ÷ 6 = 5.196152423.
I didn't round any of the numbers. Hopefully this is correct.
Sorry about the messy diagrams (never been good at creating them) and how long it took.
