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kondor19780726 [428]
2 years ago
13

Can you guys help me plz

Mathematics
1 answer:
julsineya [31]2 years ago
6 0

Answer:

1) x>1

2) x<6

3) x>34

4) x>-4

5) x<2

6) x>-36

7) x<=4

8) x>-2

9) x>=2

10) x>14

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How to simplify this problem: (4c^4)^3
hjlf

Answer:

64c^12

Step-by-step explanation:

(4c^4)^3 distribute exponents

{(4)^3 (C^12)} simplify

64c^12

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3 years ago
Sarah and Maya must split the $15 they earned, from scorekeeping a volleyball game. Sarah says, “ there’s only one way to split
Korolek [52]

Answer:

sarah is correct

Step-by-step explanation:

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4 0
2 years ago
2. Use the image below to answer problems A-C. Show all work.
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<span>A. Calculate the value of x.</span>
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3 years ago
Of 136 randomly selected adults, 33 were found to have high blood pressure. Construct a 95% confidence interval for the true of
navik [9.2K]

Answer:

The 95% confidence interval of the proportion of all adults that have high blood pressure is 0.17059 < \hat{p} < 0.314695

Step-by-step explanation:

The confidence interval for a proportion is given by the following formula;

CI=\hat{p}\pm z\times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

Where:

x = 33

n = 136

\hat{p} = x/n = 33/136 = 0.243

z value for 95% confidence is 1.96

Plugging in the values, we have;

CI=0.243\pm 1.96\times \sqrt{\frac{0.243(1-0.243)}{136}}

Which gives;

0.17059 < \hat{p} < 0.314695

Hence the 95% confidence interval of the proportion of all adults that have high blood pressure = 0.17059 < \hat{p} < 0.314695

From the above we have;

23.2 < x < 42.798

Since we are dealing with people, we round down as follows;

23 < x < 42.

4 0
2 years ago
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