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mafiozo [28]
3 years ago
11

if one letter is chosen at random from word "combed" what is the probability that the letter chosen will be a "d"

Mathematics
2 answers:
abruzzese [7]3 years ago
5 0
It would be either 1/6 or 1:6.
nalin [4]3 years ago
5 0
Total letters = 6
Total d = 1

P(d) = 1/6

Answer : 1/6
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What dose 5d-10= using two word expressions
Naddik [55]
Maybe 5 multiplying or adding the value of d subtracting 10 equals 
8 0
3 years ago
25 Points!! What is the volume of the prism 1 1/2ft 3 1/2ft 2 1/2 ft? Please answer when you have the time to.
Vladimir79 [104]

Answer:

The first one: 13.125 ft³

The second one: 67.5 ft³

Step-by-step explanation:

For the first one:

The volume of a prism is length x width x height.

So, in this shape, the length is 3 1/2, the width is 2 1/2, and the height is 1 1/2.

However, you can conver 1/2 to .5, to make it easier to multiply.

So, 3.5 x 2.5 x 1.5 = 13.125

Make sure to add ft³, the ft is the unit, feet, and the ³ is used to denote volume, because volume is 3  dimensional.

For the second one, same formula:

Length = 6, width = 2 1/2, and height = 4 1/2

6 x 2.5 x 4.5 = 67.5

Again, make sure to add ft³, the ft is the unit, feet, and the ³ is used to denote volume, because volume is 3 dimensional.

6 0
2 years ago
Read 2 more answers
A contractor developed a multiplicative time-series model to forecast the number of contracts in future quarters, using quarterl
dusya [7]

There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

H_0 :  The quarterly growth rate in the number of contracts is not  significantly different from 0% (? = 0.05)

H_a:  The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the   t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

4 0
3 years ago
Jocelyn is preparing bags for a grab bag contest at a store. Each bag will contain one coupon and one small item. The table summ
Karolina [17]

Answer:

can you explain it more please

Step-by-step explanation:

8 0
2 years ago
Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve
Akimi4 [234]
A three-dimensional vector field is conservative if it is also irrotational, i.e. its curl is \mathbf 0. We have

\nabla\times\mathbf f(x,y,z)=-2e^{-x}\,\mathbf k

so this vector field is not conservative.

- - -

Another way of determining the same result: We want to find a scalar function f(x,y,z) such that its gradient is equal to the given vector field, \mathbf f(x,y,z):

\nabla f(x,y,z)=\mathbf f(x,y,z)

For this to happen, we need to satisfy

\begin{cases}f_x=ye^{-x}\\f_y=e^{-x}\\f_z=2z\end{cases}

From the first equation, integrating with respect to x yields

f_x=ye^{-x}\implies f(x,y,z)=-ye^{-x}+g(y,z)

Note that g *must* be a function of y,z only.

Now differentiate with respect to y and we have

f_y=-e^{-x}+g_y=e^{-x}\implies g_y=2e^{-x}\implies g(y,z)=2ye^{-x}+\cdots

but this contradicts the assumption that g(y,z) is independent of x. So, the scalar potential function does not exist, and therefore the vector field is not conservative.
8 0
2 years ago
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