PLZ HELP!!
1 answer:
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Answer:
y = -3x^2 -9x +30
Step-by-step explanation:
When a polynomial has a zero at x=p, it has a factor of (x -p). The factors of your quadratic are ...
f(x) = (x +5)(x -2)
At the point x=3, the value of this product is ...
f(3) = (3 +5)(3 -2) = (8)(1) = 8
In order for that value to be -24, it needs to be multiplied by a scale factor of -3. The quadratic you want is ...
y = -3(x +5)(x -2)
y = -3x^2 -9x +30 . . . . . standard form
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Answer:
x=1 and y= 5
Step-by-step explanation:
To solve this, lets take the first equation and find the x value.
Because it is ordered in standard form, we need to convert to slope-intercept form, and isolate the y.
5x+4y=16
-5x -5x
4y=-5x+16
÷4 ÷4 ÷4
y=+4
or
y=-1+4
or
y= 5
Now that we have the y value, we can use this to find the x value by inserting it into either equation, since they both have y values in them. Going with the first one again, lets try it:
5x+4(+4)=16
5x-5+16=16
5x+11=16
-11 -11
5x=5
÷5 ÷5
x=1 and y= 5