Confused what the question is. Are you looking for the product or the zeroes?
If you are looking for the product, then:
Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)
= sec² + sec²csc² - 1 + csc²
= sec²csc² + sec² + csc² - 1
= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)
= sec²csc²
Answer: sec²csc²
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If you are looking for the zeroes, then:
Using the zero product property, set each factor equal to zero and solve.
<u>First factor:</u>
sec²Θ - 1 = 0
sec²Θ = 1
secΘ = 1, -1
remember that secΘ is 
= 1 = -1
cross multiply to get:
cosΘ = 1 cosΘ = -1
use the unit circle (or a calculator) to find that Θ = 0 and π
<u>Second factor:</u>
1 - csc²Θ = 0
1 = csc²Θ
1, -1 = cscΘ
remember that cscΘ is 
= 1 = -1
cross multiply to get:
sinΘ = 1 sinΘ = -1
use the unit circle (or a calculator) to find that Θ = 
and 
Answer: 0, π, ,
Hello,
1
.65 + 0.20(65) = 65 + 13 = 78(65 - 60) / 65 = 5/65 = 0.0769 x 100 = 7.69 rounds to 7.7 % decrease compared to the 65 pizza's sold yesterday
2.
I posted a file to help you on this question!
3. <span>Find principal by using the formula </span><span>I=P⋅i⋅t</span><span>, where </span>I<span> is interest, </span>P<span> is total principal, </span>i<span> is rate of interest per year, and </span>t<span> is total time in years.
</span>
So basically your answer is
600.I truley hope this helps.
Have a good day!
-Jurgen
Answer:
$7,562.5
Step-by-step explanation:
Given the function of the profit earned expressed as;
<em>f(p) =-40p^2+1100p</em>
To maximize the profit, df(p)/dp must be sero
df(p)/dp = -80p + 1100 = 0
-80p + 1100 = 0
-80p = - 1100
p = 1100/80
p = 13.75
Substitute p = 13.75 into the function
f(13.75) =-40(13.75)^2+1100(13.75)
f(13.75) = -7,562.5+15,125
f(13.75) = 7,562.5
Hence the symphony should charge $7,562.5 to maximize the profit.
The distance from the sun is option 2 5.59 astronomical units.
Step-by-step explanation:
Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.
Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power 
is on the variable we need to find so we multiply both the sides by an exponential power of 
to be able to calculate 'a'.
P = 
, 
= 
, = a, 
= a = 5.58533 astronomical units.
Rounding it over to nearest hundredth we get 5.59 astronomical units.
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