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Fed [463]
3 years ago
15

What is the value of x?

Mathematics
1 answer:
azamat3 years ago
4 0

Answer:

17 <u>1</u>

3

Step-by-step explanation:

= <u>67</u><u>5</u>+ <u>3</u> x = <u>53</u>

100 8 4

------------------------- × 1000

6,750+ 375x = 13,250

375x = 6,500

x = <u>6</u><u>,</u><u>5</u><u>0</u><u>0</u> = <u>2</u><u>6</u><u>0</u> = <u>5</u><u>2</u> = 17 <u>1</u>

375 15 3 3

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Mariana [72]
I need more info please!!
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3 years ago
Lisa, Susan, and Chris participated in a three person relay team. Lisa ran 1284 meters. Susan ran 1635 meters, and Chris ran 147
mars1129 [50]

Answer:

4.392 kilometers

Step-by-step explanation:

To find the length of the race in meters:

1284+1635+1473=4392 meters

Then divide by 1000 to find the length in kilometers:

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8 0
4 years ago
What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0
Free_Kalibri [48]

Answer:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, ption B is true.

Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

\sqrt{x^2y^3}=xy\sqrt{y}

2\sqrt{x^3y^4}=2xy^2\sqrt{x}

so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

                                        =2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}

Add similar elements

                                        =2xy^2\sqrt{x}+2xy\sqrt{y}

Therefore, we conclude that:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, option B is true.

6 0
3 years ago
Read 2 more answers
How many times greater is the value 34.3 than the value 3.43? Explain your thinking
Vesnalui [34]
It would 10 times great since 3.43 x 10= 34.3
4 0
3 years ago
Evaluate the piecewise-defined function for the indicated values. I’m just unsure of how to solve when the value isn’t given dir
Fantom [35]

The value of the function at t=0 is 9 , 6<x<7 is -t+5, 1<n<2 is 9, for m^{2} +1 is 9.

Given function which is 9 for 0 to 5 , -t+5 for 5 to 8 and \sqrt{t-1} for 8<t<11.

A) We have to find the function at t=0 which is 9 because it lies between 0<=t<5.

B) In this we have to find the value of the function when x=t lies between 6 and 7. is -t+5.

C) In this we have to find the value of Q(n) when n lies between 1 and 2 and the value becomes 9 because it lies between 0 and 5.

D) In this we have to find the function at m^{2} +1 when m belongs to \sqrt{7} and \sqrt{10} the value of m lies between 2 and 4 and the value of m square +1 lies between 3 and 5. Hence the value of function at m square plus one is 9.

Learn more about functions at brainly.com/question/10439235

#SPJ10

6 0
3 years ago
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