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3 years ago

How do you Evaluate. 58−(14)2= ________

Mathematics

2 answers:

Olenka [21]3 years ago

8 0

Answer:

For this case we have the following expression:

The first step is to solve the quadratic term.

We have then:

Then, the second step is to subtract both resulting numbers:

We observe that the result obtained is a negative number.

chubhunter [2.5K]3 years ago

7 0

Answer:

58-(14)2

58-28

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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2 years ago

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What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

2 years ago

Answer please! Thanks so much! :)

DanielleElmas [232]

320 is the correct answer

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2 years ago

Cdef maps to jklm with the transformation (x,y) to (4x,4y) to (x-4,y-9). What is the value of ef/lm.

Elina [12.6K]

Answer:

EF / LM = 1 / 4

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, dilation and rotation.

Dilation is the enlargement or reduction in the size of a figure. If a point A(x, y) is dilated by a scale factor of k, the new point is at A'(kx, ky).

Translation is the movement of a point right, left, up or down. If a point A(x, y) is translated a units left and b units down, the new point is at A'(x - a, y - b).

Translation preserves the size and shape of an object. Dilation preserves the shape but not the size.

Cdef maps to jklm with the transformation (x,y) to (4x,4y) to (x-4,y-9).

CDEF was first dilated by a scale factor of 4 to get (4x,4y) before it was translated by (x-4,y-9). Since dilation changes the size of the figure, hence JKLM would be 4 times the size of CDEF. Therefore:

LM / EF = 4

EF / LM = 1 / 4

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2 years ago