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KonstantinChe [14]
3 years ago
10

Plrase help ya'll I am going to rip my hair out i'm overthinking

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
5 0

Answer:

jk+kl=kl

15+16=31

mark it as brainliest!!!

vesna_86 [32]3 years ago
4 0

Answer: 31

Step-by-step explanation:

add the 2 lengths of the given parts.

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An observer for a radar station is located at the origin of a coordinate system. For the point given, find the bearing of an air
Vinvika [58]

Answer:

as the point (8,0) lies on the x-axis (east) and the bearings are defined with respect to south or north according to the rotation as well. so here the angle is 90 and the directions are N90E or S90W

5 0
3 years ago
Based on a sample survey, a principal claims that 7 out of 10 students like math. If there are 1300 students, how many would you
horsena [70]

Answer:

390

Step-by-step explanation:

find the fraction of those that don't like math

10/10 - 7/10= 3/10

then do 3/10 x 1300 to get 390

5 0
3 years ago
Only 8 9 and 10 please
sattari [20]
8) 3/16
9) 41/8
10) 218/5
3 0
3 years ago
What are double facts what do they look like
motikmotik
Double facts the even and odd numbers for example 2×2=4
7 0
3 years ago
Read 2 more answers
The following dotplot shows the centuries during which the 11 castles whose ruins remain in Somerset, England were constructed.
nasty-shy [4]

Taking into account the rule 1.5 IQR, there aren't high outliers in the displayed data set.

Calculation of the Interquartile Range and the rule 1.5 IQR.

To calculate the Interquartile Range IQR, you must subtract the value of the first quartile Q1, to the third quartile Q3, as you can see in the formula below:

IQR = Q3 - Q1

Using the five-number summary, you can replace the formula:

IQR = 17 - 13

IQR = 4

Before to apply the rule 1.5 IQR, you must multiply the IQR by 1.5:

4 * 1.5 = 6

Now, to apply the rule you must add the value obtained (6), to the third quartile (17), if any data is over this, theoretically it's an outlier:

17 + 6 = 23 (As you do not have any data over this value, it is identified that there are no outliers in the upper section).

Finally, you must subtract the value obtained (6) to the first quartile (13), if any data is under this, theoretically it's an outlier:

13 - 6 = 7 (Since you don't have any castle data built before this century, there wouldn't be any theoretically outliers either).

By this reason, using the rule of 1.5 IQR, you can see there aren't outliers in the displayed data set.

brainliest please if correct.

3 0
2 years ago
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