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netineya [11]
3 years ago
7

Calculate the area of the shaded region. Show ALL of your work

Mathematics
2 answers:
il63 [147K]3 years ago
8 0

Answer:

100

Step-by-step explanation:

The area of the non-shaded spot is 8x10, which is 80.

The area of the entire rectangle is (8+4)x(10+5) = 180.

So, to find just the shaded region, subtract the nonshaded region (80) from the entire reactangle (180) to get 100

miss Akunina [59]3 years ago
4 0

Answer:

100 i think...

Step-by-step explanation:

4+8=12, 10+5=15

12 x 15=180, 8 x 10=80

180-80= 100

Srry if this is wrong. Btw im only in 6th.

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Help pls ill mark brainliest
Naily [24]

Answer:

A. 2,310 sq ft

Step-by-step explanation:

<u>R</u><u>e</u><u>c</u><u>t</u><u>e</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>b</u><u>e</u><u>l</u><u>o</u><u>w</u><u>:</u>

  • A = l × b
  • A = 74 × 15
  • A = 1,110ft

<u>Rectangle Above</u><u>:</u>

  • A = l × b
  • A = 50 × 24
  • A = 1,200ft

<u>A</u><u>r</u><u>e</u><u>a</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>P</u><u>l</u><u>a</u><u>y</u><u>g</u><u>r</u><u>o</u><u>u</u><u>n</u><u>d</u><u>:</u>

  • 1,110ft + 1,200ft
  • 1,310 sq ft (A)
3 0
2 years ago
Find the solution(s) to (x- 3) = 49. Check all that apply.
natima [27]

Answer:

B.x= -4 and E. x= 10 are the answers

4 0
2 years ago
Plz hepl meeeeeeeeeeeee
Ira Lisetskai [31]

Answer:

5 students

Step-by-step explanation:

2/3 of 30 = 20 students

1/4 of 20 = 5 students

7 0
2 years ago
Honors Geometry QUiz- Please Help
viktelen [127]

Answer:

QUESTION 2:

The area of the polygon is 21.5 units²

QUESTION 3:

The area of the combined figure is 12 + 18.25·π units²

QUESTION 4:

The area of the figure is 40 units²

QUESTION 5

The area of the compost shape is 40 in.²

Step-by-step explanation:

QUESTION 2.

The area of the polygon is given as follows;

The area of two triangles + The area of trapezoid

1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²

QUESTION 3

The diameter of the semicircle, 'd', is given as follows;

d = √(8² + 3²) = √73

The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²

The area of the right triangle beside the semicircle is given as follows;

1/2 × 8 × 3 = 12 unit²

The area of the combined figure = The area of the semicircle + The area of the right triangle

∴ The area of the combined figure = 12 + 18.25·π units²

QUESTION 4:

The dimensions of the parallelogram are;

Width, W = √(4² + 1²) = √(17)

Length, L = √(8² + 2²) = √(68)

The area of the parallelogram, A_R = W × L = √(17) × √(68) = √(17 × 68) = 34

The area of the parallelogram, A_R = 34 units²

The length of a parallel side, 'A', of the parallelogram is A = 6

The height of the parallelogram, is h = 1

The area of the parallelogram is A = B·h = 6 × 1 = 6 units²

The area of the figure is the sum of the area of the rectangle and the area of the parallelogram

Therefore, we have;

The area of the figure = 34 units² + 6 units² = 40 units²

QUESTION 5

The composite shape consists of a triangle and a rectangle

Therefore, we have;

The area of the rectangle = 5 in. × 7 in. = 35 in.²

The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²

The area of the compost shape = The area of the rectangle + The area of the triangle

∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²

The area of the compost shape = 40 in.².

5 0
3 years ago
HELP ME WITH THIS PLEASEEEEE
strojnjashka [21]
Use the metric relations,
AC*CD=BC^2
=>
5*CD=9^2
solve for CD
CD=9*9/5=16.2
7 0
3 years ago
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