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svet-max [94.6K]
3 years ago
12

I need help in math becase I am failing again

Mathematics
2 answers:
Alja [10]3 years ago
3 0
Well you are going to
Oxana [17]3 years ago
3 0

Answers:

S. -6/7

C. 3/5

Y. -1  1/14  OR  -15/14

A. 1 7/26  OR  33/26

E. -20/21

D. -4/9

T. 3 1/3  OR  10/3

G. 2/9

I. -4 1/8  OR  -33/8

V. 3/8

O. -4 1/2  OR  -9/2

U. -2/21

N. -1/10

L. -2/9

P. 12

H. 3/7

R. 17 1/2  OR  35/2

F. -7

Those r the answers and the moral is below. Hope this helps!!

Moral:

Hugh and only Hugh can prevent florist friars


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If u-ai + bj and v-ci + dj are vectors, then which of the following statements is not true?
alukav5142 [94]

Answer:

Option C

Step-by-step explanation:

Given that u-ai + bj and v-ci + dj are vectors

We have dot product

u.v = (ai+bj).(ci+dj) hence inner product of u and v.  So option a is true

The dot product of u and v is a scalar is true because dot product is always a scalar

The dot product of u and v is a vector. is false because dot product is only a scalar and has no direction and hence cannot be a vector

The dot product of u and v is given by the expression ac+bd

True because we multiply corresponding i components and j components and add.

So only C is not true.

7 0
3 years ago
to construct a parallel to a line through a point not on the line using paper folding, you can perform the _____ construction tw
adoni [48]
<span>The <u>correct answer</u> is:

The midpoint of a segment.

Explanation<span>:

To construct a line parallel to another line through a given point, the first thing you do is fold the given line onto itself, making sure that the given point is on the fold. This is the same construction used to find the midpoint of a segment.

Unfold the paper, and the crease made with the fold creates a line through the given point and given line. Fold this new line (crease) onto itself, making sure the given point is in the fold. This is again the same construction used to find the midpoint of a segment, and this creates our parallel line through our given point.</span></span>
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What is the volume of the rectangular prism?
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8 0
2 years ago
Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin
jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

<u>GIVEN :-</u>

There are 2 right-angled triangles.

In the triangle on the right side ,

  • Hypotenuse = 26m
  • Base = 10m

In the triangle on the left side ,

  • Base = 18m

<u>TO FIND :-</u>

  • Length of the common perpendicular to both triangles.
  • Length of the hypotenuse of the triangle on the left side.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • Hypotenuse = \sqrt{Base^2 + Perpendicular^2}.
  • Perpendicular = \sqrt{Hypotenuse^2 - Base^2}

<u>SOLUTION :-</u>

In the triangle on the right side ,

Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m

∴ x = 30m

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3 years ago
A _____ is a rule that assigns each value of the independent variable to exactly one value of the dependent variable.
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I believe ur answer is fuction
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