Question

Please help I need this soon

Answer 1

Answer:

Option (3) will be the answer.

Step-by-step explanation:

Area of a triangle = $\frac{1}{2}(\text{Base})\times (\text{Height})$

                             = $\frac{1}{2}(AB)(CD)$

Since, m∠A + m∠B + m∠C = 180°

60° + 60° + m∠C = 180°

m∠C = 180° - 120°

m∠C = 60°

Therefore, ΔABC is an equilateral triangle.

AB ≅ BC ≅ AC ≅12

Sin 60° = $\frac{CD}{BC}$

$\frac{\sqrt{3}}{2}=\frac{CD}{12}$

CD = 6√3

Now area of ΔABC = $\frac{1}{2}(6\sqrt{3})(12)$

                                = $36\sqrt{3}$

                                = 62.35

                                ≈ 62.4 square units

Therefore, Option (3) will be the answer.