Question

Graph the linear equation: y = –1/5x + 3

Answer 1

Since you already have the equation in y = mx + b form, which is called the slope-intercept form, with m = slope and b = y-intercept, you can graph it easily with that information. The 3 is the y-intercept. That means point (0, 3) is where the line crosses the y-axis. Plot that point first. The slope, m = -(1/5). The slope is the rise (up or down) over the run (left or right), or rise/run. -(1/5) can be thought of (-1)/5 or as 1/(-5). Both ways are correct and work. After plotting (0, 3), using m = (-1)/3, start at (0, 3) and count one unit down, and three to the right. That's a second point on your graph. If you want a third point, you can go back to the original point, (0, 3), and now use the slope as 1/(-5). That is, from (0, 3), go 1 unit up and 5 to the left. That is a third point. Now draw a line through all three points. I hope that this is the answer that you were looking for and it has helped you.

Answer 2

I cant send an attachment but ill give you 3 points to plot it and play connect the dots
(-5,4) (0,3) (5,2)