Ask question

Ask question

All categories

3 years ago

15

Find the solution set a² = 64 Separate the two values with a comma.

2 answers:

Elza [17]3 years ago

8 0

Answer:

$\sqrt{64} , 8$

Step-by-step explanation:

$\sqrt{64}$ , 8

Just square them with a calculator and it'll be 64

mestny [16]3 years ago

4 0

Answer:

a = 8

Step-by-step explanation:

a² = 64

a = 8..

hope it's helpful

You might be interested in

PLZ ANSWER FAST I GIVE BRAINLIEST Which algebraic expression represents “the product of a number and five”?

S_A_V [24]

When two terms are directly next two each other, they are being multiplied.
The answer is 5n

7 0

3 years ago

Read 2 more answers

Which expression is equivalent to the expression 3^7x3^-4

kykrilka [37]

Answer:

3^7 * 3^(-4) = 3^(7 - 4) = 3^3 = 27

5 0

2 years ago

mark and Julie each on a sandwich shop in Missouri. last month Julie shop sold 12 more meatball sub sandwiches then Mark shop. i

Bogdan [553]

Mark: 52 meatball sandwiches
Julie: 64 meatball sandwiches

3 0

3 years ago

What rations form a proportion ?

igomit [66]

⅔ and 8/12 form a proportion.

7 0

3 years ago

7. Are the ordered pairs below an arithmetic sequence or geometric

DochEvi [55]

Answer:

8. Arithmetic Progression

9. $f(9) = 300$

Step-by-step explanation:

Given

$\{(1,55)\ (2, 45)\ (3, 35)\ (4, 25)\}$

Solving (8): Arithmetic or Geometric

We start by checking if it is arithmetic by checking for common difference (d).

$d = y_2 - y_1 = y_3 - y_2 = y_4 - y_3$

This gives:

$d = 45 - 55 = 35 - 45 = 25 - 35$

$d = -10 = -10 = -10$

$d=-10$

<em>Because the common difference is equal, then it is an arithmetic progression</em>

<em></em>

Solving (8):

$f(n) = f(1) + f(n-1)$

To find f(9), we substitute 9 for n

$f(9) = f(1) + f(9-1)$

$f(9) = f(1) + f(8)$

We need to solve for f(8); substitute 8 for n

$f(8) = f(1) + f(8 - 1)$

$f(8) = f(1) + f(7)$

We need to solve for f(7); substitute 7 for n

$f(7) = f(1) + f(7 - 1)$

$f(7) = f(1) + f(6)$

We need to solve for f(6); substitute 6 for n

$f(6) = f(1) + f(6 - 1)$

$f(6) = f(1) + f(5)$

We need to solve for f(5); substitute 6 for n

$f(5) = f(1) + f(5 - 1)$

$f(5) = f(1) + f(4)$

From the function, f(4) = 25 and f(1) = 55.

So:

$f(5)=55 + 25$

$f(5)=80$

$f(6) = f(1) + f(5)$

$f(6) = 55 + 80$

$f(6) = 135$

$f(7) = f(1) + f(6)$

$f(7) = 55 + 135$

$f(7) = 190$

$f(8) = f(1) + f(7)$

$f(8) = 55 + 190$

$f(8) = 245$

$f(9) = f(1) + f(8)$

$f(9) = 55 + 245$

$f(9) = 300$

8 0

3 years ago