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Elden [556K]
3 years ago
14

What is the range of y=log^2(x-6)

Mathematics
2 answers:
Alborosie3 years ago
8 0

Answer:

Ans: All real numbers

Step-by-step explanation:

Marysya12 [62]3 years ago
6 0

Answer:

y\geq 0 or [0, \infty)

Step-by-step explanation:

By definition the function

y = log (x) has a domain of x> 0.

Since the function is not defined for the values of x negative or equal to zero.

The range of this function is all the real numbers.

Since y when 0 and y\geq0 when 1\leq x

In this case we have the function y = log ^ 2 (x-6)

Therefore since the log function is squared then its range is now y\geq 0

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36 1/2 divide by 29 1/4
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Answer:


Step-by-step explanation:

73/2  : 117/4

=73/2 . 4/117

=146/117

=1.247

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3 years ago
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Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels at 75 miles per
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Let the time = x

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One train is 75x, the other train 85x

Add together to equal total distance:

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Simplify:

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x = 384 / 160

x = 2.4 hours

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Show your mastery of equivalent and simplifying fractions by using the sketchpad below to write the fraction
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3 years ago
What is the volume of a box that is 16 by 14?​
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Answer:

I need the length, width, and height

Step-by-step explanation:

3 0
3 years ago
4x2 + 9y2 = 72<br> 2x - y = 4<br><br> Which of the following is a solution to the system shown?
Ede4ka [16]
If you would like to solve the system of equations, you can do this using the following steps:

4x^2 + 9y^2 = 72
2x - y = 4 ... 2x - 4 = y
_________
<span>4x^2 + 9y^2 = 72
</span><span>4x^2 + 9 * (2x - 4)^2 = 72
</span>4x^2 + 9 * (4x^2 - 16x + 16) = 72
4x^2 + 36x^2 - 144x + 144 = 72
40x^2 - 144x + 144 - 72 = 0
40x^2 - 144x + 72 = 0
10x^2 - 36x + 18 = 0
5x^2 - 18x + 9 = 0
(5x - 3) * (x - 3) = 0
1. 5x - 3 = 0 ... 5x = 3 ... x = 3/5
2. x = 3

<span>1. y = 2x - 4 = 2 * 3/5 - 4 = 6/5 - 20/5 = -14/5
2. y = 2x - 4 = 2 * 3 - 4 = 6 - 4 = 2

1. (x, y) = (3/5, -14/5)
2. (x, y) = (3, 2)

The correct result would be </span>(3/5, -14/5) and <span>(3, 2).</span>
5 0
3 years ago
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