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3 years ago

7/3 * 7/3 As a mixed number and it must be in simplest form

Mathematics

2 answers:

Tema [17]3 years ago

5 0

Answer:

2 1/3

Step-by-step explanation:

2 1/3

Simora [160]3 years ago

3 0

Answer:

2- 1/3 7/3

Step-by-step explanation:

Here we will simplify 7/3 to its simplest form and convert it to a mixed number if necessary.

In the fraction 7/3, 7 is the numerator and 3 is the denominator.

When you ask "What is 7/3 simplified?", we assume you want to know how to simplify the numerator and denominator to their smallest values, while still keeping the same value of the fraction.

We do this by first finding the greatest common factor of 7 and 3, which is 1.

Then, we divide both 7 and 3 by the greatest common factor to get the following simplified fraction:

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What is the location of the second endpoint if the first endpoint is at (5,2) and

RUDIKE [14]

The second midpoint is (-15,8)

5 0

3 years ago

Fill in the boxes below with the numbers 1-5.

Alja [10]

Answer:

4 - 2 - 3 - 1 - 5

Step-by-step explanation:

The substitute method consists of the following steps:

Solve for either x or y in one of the equations.
Substitute the expression you got into the other equation
Simplify and solve for the variable that remains.
Back substitute and solve for the first variable.
Check your solution

3 0

3 years ago

Read 2 more answers

(2 x 106) x (0.00009) = ?

RSB [31]

I think you meant to write

(2 × 10⁶) × 0.00009

First, convert 0.00009 to scientific notation:

0.00009 = 9 × 10 ⁻⁵

Then

(2 × 10⁶) × 0.00009 = (2 × 10⁶) × (9 × 10 ⁻⁵)

… = (2 × 9) × (10⁶ × 10 ⁻⁵)

… = 18 × 10¹

… = 1.8 × 10²

4 0

3 years ago

A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar

Elenna [48]

Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ounces, with a sample standard deviation of 0.052 ounces.

Let $\mu$ = population mean amount packaged.

So, Null Hypothesis, $H_0$ : $\mu$ = 8.17 ounces {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 8.17 ounces {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean amount dispensed = 8.171 ounces

s = sample standard deviation = 0.052 ounces

n = sample of packages = 50

So, the test statistics = $\frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }$ ~ $t_4_9$

= 0.1359

The value of t-test statistics is 0.1359.

Also, the P-value of test-statistics is given by;

the meaning of the p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

P-value = P( $t_4_9$ > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

6 0

3 years ago

Estimate 34,182-18,717 by first rounding each number to the nearest thousand.

tresset_1 [31]

Answer:

15,000

Step-by-step explanation:

First, round both the numbers:

34,182 rounds down to 34,000

18,717 rounds up to 19,000

Subtract you're two rounded numbers

34,000 - 19,000 = 15,000

6 0

3 years ago