Answer:
a = 3
b = 4
Step-by-step explanation:
Simultaneous equation
3a = 2b + 1
3a - 2b = 1 ------------------(I)
3b = 5a - 3
-5a + 3b = -3 --------------(II)
Multiply equation (I) by 3 & equation (II) by 2 and then add. So, now 'b' will be eliminated and we can find the value of 'a'.
(I)*3 9a - 6b = 3
(II)*2 <u>-10a + 6b = -6</u> {Now add}
-a = -3
a = -3/(-1)
Plugin a = 3 in equation (I)
3*3 - 2b = 1
9 - 2b = 1
-2b = 1 - 9 {Subtracting 9 from both sides}
-2b = - 8
b = (-8)/(-2) {Dividing both sides by (-2_}
<u>The answer is A. Multiply both sides of the top equation by 2</u>
So since we know that 4 × 2 = 8, it would only make sense to multiply both sides by 2 so that the top equation has the x coefficient be 8.
Answer:
93
Step-by-step explanation: The first term of AP is -5 and second term means -3.
Common difference(d) = second term - first term
d = (-3)-(-5)
d= 2
Now using the formula of nth T
n
=a
1
+(n−1)d
Here a
1
=−5,n=50,d=2
Puting these values in the formula of of nth term we get
a
n
=−5+(50−1)2
a
n
=−5+98
a
n
=93
HELP ME PLEASE! I need to find the Interquartile range of : 0,0,0,1,1,3,3,3,4,4,4,6,6,7,7,7,8,8,9,10
Lana71 [14]
Answer:
The interquartile range is 5
2 goes into both numbers, so divide both by 2;
10 ÷ 2 = 5
42 ÷ 2 = 21
so 10/42 in simplest form is: 5/21
