Step-by-step explanation:
We can use the formula to find the number of moles. As ,
n = No. of particles/ N_A
n = 3.01× 10¹⁸/6.022 × 10²³
n = 1/2 / 10⁵
The Clayton family’s pool has vertices at the coordinates (0, 2), (0, 5), (2, 5), (2, 6), (5, 6), (5, 1), (2, 1), and (2, 2). If
each grid square has an area of 9 square feet, what is the area of the pool?
Ps. Only use the coordinates (Do not use a coordinate table)
And explain how to show the work, thanks.
Ps. Only use the coordinates (Do not use a coordinate table)
And explain how to show the work, thanks.
2 answers:
We should start by plotting these points on the coordinate plan and drawing the pool.
Looking at the diagram I've attached, we can split the pool into two rectangles and find the area of each.
For the smaller rectangle, with vertices
, the length is 3 units and the width is 2 units. 
For the larger rectangle with vertices
, the length is 5 units and the width is 3 units. 
Now remember, each square unit on the coordinate plane represents 9 square feet, so we write:
Looking at the diagram I've attached, we can split the pool into two rectangles and find the area of each.
For the smaller rectangle, with vertices
For the larger rectangle with vertices
Now remember, each square unit on the coordinate plane represents 9 square feet, so we write:
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negative angles, are just angles that go "clockwise", namely, the same direction a clock hands move hmmm so.... and one revolution is just 2π
now, you can have angles bigger than 2π of course, by simply keep going around, so, if you go around 3 times on the circle, say "counter-clockwise", or from right-to-left, counter as a clock goes, 3 times or 3 revolutions will give you an angle of 6π, because 2π+2π+2π is 6π
now... say... you have this angle here... let us find another that lands on that same spot
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now, that's a positive one
and
to get more, just keep on subtracting or adding 2π