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Leni [432]
3 years ago
10

What is episodic memory? knowledge about words, concepts, and language-based knowledge and facts information about events we hav

e personally experienced storage of facts and events we have personally experienced type of implicit memory that stores information about how to do things
Computers and Technology
1 answer:
tankabanditka [31]3 years ago
3 0

Answer:

<em>information about events we have personally experienced</em>

Explanation:

Episodic memory is <em>the actual memory of a particular event that a person has, so it will be different from the recall of the same encounter or experience by someone else.</em>

Often, episodic memory is mistaken with autobiographical memory, and while autobiographical memory includes episodic memory, it also depends on semantic memory.

<em>For instance, you might know the city you were born in and the date, though you have no particular birth memories.</em>

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1. The following programs require using arrays. For each, the input comes from standard input and consists of N real numbers bet
Mamont248 [21]

Answer:

import java.util.*;

import java.io.BufferedReader;

import java.io.IOException;

import java.io.InputStreamReader;

import java.util.Arrays;

class GFG

{

  // Function for calculating mean

  public static double findMean(double a[], int n)

  {

      int sum = 0;

      for (int i = 0; i < n; i++)

          sum += a[i];

 

      return (double)sum / (double)n;

  }

  // Function for calculating median

  public static double findMedian(double a[], int n)

  {

      // First we sort the array

      Arrays.sort(a);

      // check for even case

      if (n % 2 != 0)

      return (double)a[n / 2];

 

      return (double)(a[(n - 1) / 2] + a[n / 2]) / 2.0;

  }

  public static double findMode(double a[], int n)

{

// The output array b[] will

// have sorted array

//int []b = new int[n];

 

// variable to store max of

// input array which will

// to have size of count array

double max = Arrays.stream(a).max().getAsDouble();

 

// auxiliary(count) array to

// store count. Initialize

// count array as 0. Size

// of count array will be

// equal to (max + 1).

double t = max + 1;

double[] count = new double[(int)t];

for (int i = 0; i < t; i++)

{

count[i] = 0;

}

 

// Store count of each element

// of input array

for (int i = 0; i < n; i++)

{

count[(int)(10*a[i])]++;

}

 

// mode is the index with maximum count

double mode = 0;

double k = count[0];

for (int i = 1; i < t; i++)

{

if (count[i] > k)

{

k = count[i];

mode = i;

}

}

return mode;

}

public static double findSmallest(double [] A, int total){

Arrays.sort(A);

return A[0];

}

 

public static void printAboveAvg(double arr[], int n)

{

 

// Find average

double avg = 0;

for (int i = 0; i < n; i++)

avg += arr[i];

avg = avg / n;

 

// Print elements greater than average

for (int i = 0; i < n; i++)

if (arr[i] > avg)

System.out.print(arr[i] + " ");

System.out.println();

}

 

public static void printrand(double [] A, int n){

Arrays.sort(A);

for(int i=0;i<n;i++){

System.out.print(A[0]+"/t");

}

System.out.println();

}

 

public static void printHist(double [] arr, int n) {

 

for (double i = 1.0; i >= 0; i-=0.1) {

System.out.print(i+" | ");

for (int j = 0; j < n; j++) {

 

// if array of element is greater

// then array it print x

if (arr[j] >= i)

System.out.print("x");

 

// else print blank spaces

else

System.out.print(" ");

}

System.out.println();

}

// print last line denoted by ----

for(int l = 0; l < (n + 3); l++){    

System.out.print("---");

}

 

System.out.println();

System.out.print(" ");

 

for (int k = 0; k < n; k++) {

System.out.print(arr[k]+" ");

}

}

  // Driver program

  public static void main(String args[]) throws IOException

  {

      //Enter data using BufferReader

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

double [] A = new double[100];

int i=0;

System.out.println("Enter the numbers(0.0-1.0) /n Enter 9 if u have entered the numbers. /n");

do

{

A[i++]=Double.parseDouble(br.readLine());

}while(A[i-1]==9);

      i--;

      System.out.println("Average = " + findMean(A,i) );

      System.out.println("Median = " + findMedian(A,i));

      System.out.println("Element that occured most frequently = " + findMode(A,i));

      System.out.println("number closest to 0.0 =" + findSmallest(A,i));

      System.out.println("Numbers that are greater than the average are follows:");

      printAboveAvg(A,i);

      System.out.println("Numbers in random order are as follows:");

      printrand(A,i);

      System.out.println("Histogram is bellow:");

      printHist(A,i);

  }

}

Explanation:

3 0
3 years ago
You started using a new Windows server three months ago. Since that time, you have found that the system slows down and crashes
Brut [27]

Answer: Open Reliability Monitor.

Explanation:

The simplest way to view this information is to open the reliability monitor.

The Reliability Monitor shows you the stability history of a system at a glance and also allows one to see the details of the events that has an effect on reliability on a daily basis.

The reliability and problem history chart which can be seen in the Reliability Monitor helps in keeping track of the overall health of the server on a daily basis.

4 0
3 years ago
Host B on subnet Teachers transmits a packet to host D on subnet Students. Which Layer 2 and Layer 3 addresses are contained in
mr Goodwill [35]

Answer:

Layer 2 destination address = 00-00-0c-94-36-ab

Layer 2 source address = 00-00-0c-94-36-bb

Layer 3 destination address = 172.16.20.200

Layer 3 source address = 172.16.10.200

Explanation:

To properly understand the given answer, let us define some terms used in the narrative of the question:

Subnet: The sub network or as popularly called subnet  is a logical division of the internet protocol of a network into many different and smaller network. It is typically used to create partitions or subdivisions of large networks into bits.

PDU: The PDU can be said to be an abbreviation for the word power distribution unit or protocol data unit.  It can also be refereed to as an IT device that possess many output ports or terminals. They are mostly used to distribute or transmit power or data to other operating devices with the telecommunication system.

Now referring back to the question asked and the image attached below, we can see that host a and b send their signal through subnet teachers while host c and d send their signal through subnet students thus,

Layer 2 destination address = 00-00-0c-94-36-ab

Layer 2 source address = 00-00-0c-94-36-bb

Layer 3 destination address = 172.16.20.200

Layer 3 source address = 172.16.10.200 are the correct destination.

4 0
3 years ago
Hey yall! Its spoopy season! I am having a live stream on the Spoon app under the username teendragonqueen️‍ if yall wanna join!
irina1246 [14]

Answer:

im down for that

Explanation:

4 0
3 years ago
The term _____ distinguishes the person who uses a hardware or software product from the IT workers who develop, install, servic
adell [148]

Answer:

"It user" is the correct answer for the above question.

Explanation:

  • It users are the user who is generally using the computers and the It system for their work.
  • But the It workers works is to install the service and to develop the service for the IT users.
  • Hence anybody can say that there is a many difference between It user and the IT workers.
  • The above question-statement also wants to states the same difference between the IT user and the It workers. So after putting the "it user" in the above question blanks the statement means the same. Hence "IT user" is the correct answer.
8 0
4 years ago
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