Pleasee help. How do you fix this problem in discord?

Which best describes inserting a table using the Table Gallery

balandron [24]

The table gallery is to help you create the table.

4 0

3 years ago

Read 2 more answers

4.2.5 codehs text messages answer

N76 [4]

Answer:

public class TextMessage

{

private String message;

private String sender;

private String receiver;

public TextMessage(String from, String to, String theMessage)

{

sender = from;

receiver = to;

message = theMessage;

}

public String toString()

{

return sender + " texted " + receiver + ": " + message;

}

4 0

2 years ago

Employees at the Red Bluff Golf Club & Pro Shop have the opportunity to become certified trainers if they log enough hours.

vodka [1.7K]

Answer:

Following are the solution to this question:

Explanation:

Some of the data is missing in the question, which is defined in the attached file. Please find it.

Follows are the formula which is used in the question:

EmployeeAnalysis Worksheet IF(C5>49,"Certified","Not Certified")

Transactions Worksheet IF(F10="No","",0.07)

In the first condition, it checks "C5" is greater than 49 if the condition is true, it will give "Certified" otherwise, it will give "Not Certified".

In the second condition, it checks "F10" is equal to "No" if the condition is true, it will give a blank or space otherwise, it will give "0.07".

3 0

3 years ago

Imagine that one of your clients has complained to your manager that you have not responded quickly to his e-mails. Compose an e

Galina-37 [17]

Dear Mr. _____,
I am truly sorry for the inconvenience and I promise to work faster to more quickly solve your problem so that you can continue to enjoy your day without worrying about the situation. Next time I will respond back faster to ensure that your problem is fixed as quickly as possible.

Sincerely,
_____________

6 0

3 years ago

Given the lists list1 and list2, not necessarily of the same length, create a new list consisting of alternating elements of lis

tester [92]

Answer:

The following code is written in Python Programming Language.

Program:

list1=[1,2,3]

# initialized the list type variable

list2=[4,5,6,7,8]

# initialized the list type variable

list3=[]

# initialized the empty list type variable

for j in range(max(len(list1), len(list2))): #set for loop

if j<len(list1):

#set if statement

list3.append(list1[j])

#value of list1 appends in list3

if j<len(list2):

#set if statement

list3.append(list2[j])

#value of list2 append in list3

print(list3) #print the list of list3

Output:

[1, 4, 2, 5, 3, 6, 7, 8]

Explanation:

Here, we define three list type variables "list1", "list2", "list3" and we assign value in only first two variables "list1" to [1, 2, 3] and "list2" to [4, 5, 6, 7, 8] and third list is empty.

Then, we set the for loop and pass the condition inside it we pass two if conditions, in first one we compare the list1 from variable "j" inside it the value in list1 will append in list3, and in second one we compare "j" with list two and follow the same process.

After all, we print the list of the variable "list3".

5 0

3 years ago