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4 years ago

20×+4=4(5x+1) how many solution are in this equation

Mathematics

1 answer:

Tomtit [17]4 years ago

7 0

Simplify both sides of the equation

(20)(4)= 4(5x+1)

Simplify

80 = 20x+4

Flip the equation

20x+4 = 80

Subtract 4 from both sides

20x+4-4 = 80-4

20x = 76

Divide both sides by 20

20x/20 = 76/20

x= 3.8

There is one solution in this equation

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Answer:

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Step-by-step explanation:

Given expression is $-8x^5y^2\times 6x^2y$

To find the product of the given expression:

The product of the given expression can be written as

$-8x^5 y^2\times 6x 2y=(-8x^5y^2)(6x^2y)$

$=(-8x^5y^2)(6x^2y)$

$=-48(x^5\times x^2)(y^2\times y^1)$ [since $a^m\times a^n=a^{m+n}$ ]

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Therefore the product of the given expression $-8x^5y^2\times 6x^2y$ is $-48x^7y^3$

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