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dem82 [27]
3 years ago
9

Find two consecutive even intergers whose sum is 34

Mathematics
1 answer:
Daniel [21]3 years ago
3 0
Ask safari it gives you the best answer
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What is the range of the function g(t)=t2−5 g ( t ) = t 2 − 5 when the domain is defined as the set of integers, t, t , such tha
Andrej [43]

g(t) = t² - 5

g(-4) = (-4)² - 5   = 16 - 5   = 11

<em>at this point, you can tell that B is the answer, but I will continue on so you know how to solve similar problems.</em>

g(-3) = (-3)² - 5   = 9 - 5   = 4

g(-2) = (-2)² - 5   = 4 - 5   = -1

g(-1) = (-1)² - 5   = 1 - 5   = -4

g(0) = (0)² - 5   = 0 - 5   = -5

g(1) = (1)² - 5   = 1 - 5   = -4

g(2) = (2)² - 5   = 4 - 5   = -1

Answer: B

5 0
3 years ago
Can you write a rule for finding the output (absolute guessing error) given the input (a guess)?
igor_vitrenko [27]

Answer:

The rule for the plotted line is y = \left | x - 50 \right |

Step-by-step explanation:

The coordinates when y = 0, x = 50

When y = 10, x = 60

Therefore, the slope = (10 - 0)/(60 - 50) = 1

The equation in slope and intercept form is y - 10 = 1 × (x - 60)

y = x -60 + 10 = x -50

y = x - 50

Also, we have

When y = 20, x = 30

y = 10, x = 40

Therefore, the slope = (10 - 20)/(40 - 30) = -1

The equation in slope and intercept form is y - 10 = -1 × (x - 40)

y = -x + 40 + 10

y = 50 - x

Therefore, when x < 50, y = 50 - x

When x > 50, y = x - 50

Which is equivalent to y = \left | x - 50 \right |

The rule for the plotted line is y = \left | x - 50 \right |

5 0
3 years ago
2. At the test center giving the exam from the previous problem, the firm needs to plan for proper staffing. Historical data sug
kozerog [31]

Answer:

a) I would use the following distribution fir the amount of applicants arriving in a 20 minute period

P_X(k) = \frac{e^{-1.5} \, * \, 1.5^k}{k!}

b) In a 50 hour period, we will expect to need 0.4679*50 = 23.3948 hours with the extra staff member

Step-by-step explanation:

a) For a total amount of arrivals in a 20 minute period i would use a Poisson distribution with parameter λ = 1.5 (the average). The distribution X is given by this formula

P_X(k) = \frac{e^{-1.5} \, * \, 1.5^k}{k!}

b) For one hour, the average will be 1.5*60/20 = 4.5 applicants. The distribution Y for the amount of applicants in one hour is given by the following formula

P_Y(k) = \frac{e^{-4.5} \, * \, 4.5^k}{k!}

First, we want to find the probability of Y being greater then or equal to 5. We can obtain the probability of the complementary event and substract it from 1. That event is equal to the probability of Y being equal to 0,1,2,3 or 4

P(Y=0) = e^{-4.5}

P(Y=1) = e^{-4.5}* 4.5

P(Y=2) = e^{-4.5} * 4.5²/2 = e^{-4.5} * 10.125

P(Y=3) = e^{-4.5} * 4.5³/6 = e^{-4.5} * 15.1875

P(Y=4) = e^{-4.5} * 4.5⁴/24 = e{-4.5} * 17.08594

Thus,

P(Y < 5) = P(Y=0)+P(Y=1)+P(Y=2)+P(Y=3)+P(Y=4) = e^{-4.5} * (1+4.5+10.125+15.1875+17.08594) = 0.5321

Therefore,

P(Y ≥ 5) = 1-0.5321 = 0.4679

In a 50 hour period, we will expect to need 0.4679*50 = 23.3948 hours with the extra staff member.

5 0
4 years ago
Frist one gets brainist the questions are all the the picture ​
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4) 4m, 18, and g
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7 0
3 years ago
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Find the circumference of the circle with the given radius. Round to the nearest tenth. Use 3.14 for π.
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16.3 cm that is the answer
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