D because you need to make the denominators have a common multiple.
Answer:
Hey mate....
Step-by-step explanation:
This is ur answer.....
<h3>
<em>Points L, J, and K are collinear.</em></h3>
Hope it helps you,
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Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
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Answer: for example (-2,-2), (-3,-6), and (-8,-10)
Step-by-step explanation: every point in the third quadrant is both negative.
Step-by-step explanation:
4/9A = 12
A = 12×9/4
= 27
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