Answer:
The required confidence interval is (3.068,4.732)
Step-by-step explanation:
Consider the provided information.
He plans to use a 90% confidence interval. He surveys a random sample of 50 students. The sample mean is 3.90 alcoholic drinks per week. The sample standard deviation is 3.51 drinks and wants to construct 90% confidence interval.
Thus, n=50,
=3.90 σ=3.51
Now find degree of freedom.

The confidence level is 90% and df=49
Therefore,


Now by using t distribution table look at 49 df and alpha level on 0.05.

Calculate SE as shown:


Now multiply 1.67653 with 0.4964
Therefore, the marginal error is: 1.67653 × 0.4964≈ 0.832
Now add and subtract this value in given mean to find the confidence interval.

Hence, the required confidence interval is (3.068,4.732)
Answer:
Im sorry bro but there's no picture
Step-by-step explanation:
2.50 (5) = 12.5
she owes 12 dollars and 50 cents
A is 6:55
B is 37 Minutes
C is 15:12
Step-by-step explanation:
so basically its just adding minutes to a clock, like if its 1:00 o clock and 40 minutes pass it will be 1:40 or if its 12:00 and 25 minutes pass it will be 12:55. There's 60 minutes in an hour so if the time is, let's say, 12:45 and 30 minutes go by itd be 1:15.
C is a little more tricky but thats just because its military time.:) basically instead of going to 12 am to 1 pm it would go from 12:00 AM to 13:00 PM